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3 years ago

2 1/4 pounds of chocolate cost $9.00. What is the price per pound?

Mathematics

2 answers:

garik1379 [7]3 years ago

8 0

9/2.25= $4 per pound is the answer to the question

melisa1 [442]3 years ago

7 0

4 dollars per pound.

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What two numbers multiply to -84 and add up to 17

allsm [11]

The two numbers are 21 and -4 because 21×(-4)=(-84). And when you add 21+(-4) you get 17.

4 0

3 years ago

An employee worked 160.5 hours in may, 165.75 hours in June and 152.25 hours in july.

Vaselesa [24]

To find the average, you have to add everything up and divide by the amount that you have. In this case, you need to add together 160.5, 165.75 and 152.25, and then divide by 3.
160.5+165.75+152.25= 478.5
You've then got to divide this by three.
478.5/3= 159.5
Therefore, the average hour worked each month bu the employee is 159.5
Hope this helps :)

5 0

3 years ago

Sales tax in your community is 5. 25 cents for each dollar spent. What is the total cost at the movies for three tickets at

Montano1993 [528]

Answer:

33.94

Explanation:

First start off by finding the total regardless of the 5.25 cents.

(3x8.50)+(3x1.25)+(2x1.50)=32.25

Then take that answer and multiply by your 5.25 cents per dollar

32.25x.0525 (since we're dealing with money)

then add that answer to the original 32.25

8 0

2 years ago

The 42km drive from Oakdale to Ridgemont usually takes 28 minutes. Because a highway construction requires a reduced speed limit

Evgesh-ka [11]

Answer:

60 km/h

Step-by-step explanation:

At the reduced speed, the trip takes 28 +14 = 42 minutes to drive 42 km. That's 1 km per minute, or 60 km in 60 minutes.

The reduced speed is 60 km/h.

8 0

3 years ago

Rationalize the denominator.

Maslowich

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166412

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$\mathsf{\dfrac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}-2\sqrt{y}}}$

Multiply and divide by the conjugate of the denominator, which is $\mathsf{\sqrt{a}+2\sqrt{y}:}$

$\mathsf{=\dfrac{\big(\sqrt{a}+2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}{\big(\sqrt{a}-2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}}\\\\\\ \mathsf{=\dfrac{\big(\sqrt{a}+2\sqrt{y}\big)^2}{\big(\sqrt{a}-2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}}$

The numerator is a square of a sum, and the denominator is the product of a difference and a sum (product of two conjugates). Then, expand the common products:

$\mathsf{=\dfrac{\big(\sqrt{a}\big)^2+2\cdot \sqrt{a}\cdot 2\sqrt{y}+\big(2\sqrt{y}\big)^2}{\big(\sqrt{a}\big)^2-\big(2\sqrt{y}\big)^2}}\\\\\\ \mathsf{=\dfrac{a+4\cdot \sqrt{a}\cdot \sqrt{y}+2^2\cdot \big(\sqrt{y}\big)^2}{a-2^2\cdot \big(\sqrt{y}\big)^2}}$

$\mathsf{=\dfrac{a+4\sqrt{ay}+4y}{a-4y}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

8 0

3 years ago