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alexandr402 [8]
3 years ago
13

How many unique values of x solve x2 + 14x + 49 = 0?

Mathematics
1 answer:
Natalka [10]3 years ago
3 0
I think x= -7 but I'm not to sure
You might be interested in
A parking lot covers 32,420 square feet .what id its area to the nearest thousand feet
Mademuasel [1]

Answer: 32,000

Step-by-step explanation:

the thousands place (1000) is the fourth number to the left of the decimal, so round that one either up or down based on the number just one spot closer to the decimal, in this case, the hundreds place (100).

so we have 32,420

we can ignore the numbers that are going to become zeros as a result of the rounding . .

32,400

let's round 32,XXX either up or down based on the value in the hundreds place. if that value is 5 or greater, than we round up. if it is less than 5, than we round down.

4 is in the hundreds place, so we round down

32,000 is the answer

Hope this helps!!! Good luck!!! ;)

6 0
3 years ago
Please help! Correct answer only!
kykrilka [37]
55 - 3 = 52
52 - 3 = 49
49 - 3 = 46
46 - 3 = 43
43 is your answer
7 0
3 years ago
Help Please really do need help
Ksju [112]

Answer:

your answer would be a whole number, so your answer would be 1,000 i think.

this should be the answer because if you multiply

9*1000 you get  9000

if you multiply

25 * 1000 you get 25000

so on and so on

Step-by-step explanation:

hope this helps :)

5 0
2 years ago
Help me with this pls
kozerog [31]

Answer:

x=2  y=17

Step-by-step explanation:

53/17       17x3 = 51     53-51     3 + 1/   x + 1/y

8 0
2 years ago
Read 2 more answers
The town of madison has a population of 25,000. The population is increasing by a factor of 1.12 each year. Write a function tha
GaryK [48]
<h3>The population P(t) at the end of year t is   P(t)   = 25,000 \times (1.12)^t</h3>

Step-by-step explanation:

The initial population of town of Madison = 25,000

The rate at which the population is increasing = 1.12 times

So, the increase in population first year  :

( the initial population)  x (1.12)^1  = 1.12 x ( 25,000)  

= 28,000

So, the population at the end of first year = 28,000

Similarly, the increase in population second year  :

( the initial population)  x (1.12)²  =  ( 25,000)   x (1.12)²

= 31,360

So, the population at the end of second year =31,360

Now, to calculate the population in t years from now:

The population P(t) at the end of year t is

P(t)   = 25,000 \times (1.12)^t

5 0
3 years ago
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