Which of these numbers is irrational? a)2.3 b)sqrt 3 c)sqrt 4 d)1/3

Mathematics

2 answers:

AveGali [126]3 years ago

8 0

B it is a surd and surds are irrational

german3 years ago

8 0

The square root of 3 (b). The reason why is because it cannot be shown as the ratio of two numbers.
You can find out more here: https://www.khanacademy.org/math/algebra/rational-and-irrational-numbers/alg-1-irrational-numbers/v/...

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For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed wi

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Explanation:

Lets interpret Z with M trials. First we have M trials, each trial can be a success or not. The number of success is called N. Each trial that is a success becomes a trial, and if it is a success it becomes a success for Z. Thus, in order for a trial to be successful, it needs first to be successful for the random variable N (and it is with probability q), and given that, it should be a success among the N trials of the original definition of Z (with probability p).

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2 years ago

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anzhelika [568]

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3 years ago

FIND (-8/3)+(-1/4)+(-11/6)+3/8-3

emmainna [20.7K]

Answer:

-7 3/8

Step-by-step explanation:

The least common denominator of 3, 4, 6, and 8 is 24; converting all of our fractions to that denominator and solving, we have

$-\frac{8}{3}+\left(-\frac{1}{4}\right)+\left(-\frac{11}{6}\right)+\frac{3}{8}-3\\=-\frac{64}{24}+\left(-\frac{6}{24}\right)+\left(-\frac{44}{24}\right)+\frac{9}{24}-3\\\\=\frac{-64+(-6)+(-44)+9}{24} -3\\\\=\frac{-70+(-44)+9}{24} -3\\\\=\frac{-114+9}{24} -3\\\\=\frac{-105}{24}-3 \\\\=\frac{-35}{8}-3\\ \\=-4\frac{3}{8}-3\\\\=-7\frac{3}{8}$

So our solution is -7 3/8

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zhuklara [117]

Answer:

picture from Goldbach's conjecture.

Step-by-step explanation:

Goldbach's conjecture is one of the oldest and best-known unsolved problems in number theory and all of mathematics. It states:

Every even integer greater than 2 is the sum of two primes.

The conjecture has been shown to hold for all integers less than 4 × 10^18, but remains unproven despite considerable effort.

So on the red and blue axes you see primes. The list of black numbers are even numbers.

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IgorLugansk [536]

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2 years ago