Step-by-step explanation:Let number of 49 cents =A
Let number of 33 cents=B
<u>A+B=45 equation 1</u>
1 $=100 cents
49 cents =.49 dollar
33 cents=.33 dollar
so .<u>49A+.33B=17.89 equation 2</u>
Add equation 1 and equation 2
since these are simultaneous equations
.49A+.33B=17.89
A+ B=45
so divide equation 2 by 100 we get
49A+33B=1789
A+B =45 multiply equation 1 by 33 on both the sides we get
<u>33A+33B=1485 equation 3</u>
so subtract equation 3 from equation 2 we get
49A+33B=1789 equation 2
<u>33A+33B=1485 equation 3</u>
<u>16A+0 =304</u>
16A=304
A=304/16
A=19
putting nalue of A in equation 1 we get
A+B=45
19+B=45
B=45-19
B=26
so number of 49 cent stamps are 19
and number of 33 cent stamps are 26
Y= -7.5 that is the answer youre welcome
Answer:
-13n + 101
Step-by-step explanation:
88, 75, 62, 49. = -13 -13 -13 = -13n + 101 (as 88+13 = 101)
Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side. The height of the tringle is 24 units. Hence option 2 is the correct option.
<h3>Given information-</h3>
The triangle for the given problem is shown in the image below.
Form the figure the length of the each side is
units.
As all the sides are equal thus the
is a equilateral triangle in which the height of the divides the triangle into two equal part of the length
at point <em>R.</em>
<h3>Height of the triangle-</h3>
Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side.
Now in the
, the length of the hypotenuse is
units and the length of the base is
units. Let <em>h </em>is the height of the triangle thus by the Pythagoras theorem,

Solve for <em>h,</em>
<em />
<em />
<em />
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Thus the height of the tringle is 24 units. Hence option 2 is the correct option.
Learn more about the equilateral triangle here;
brainly.com/question/4268382