What is the solution set for 12=2(3x - 7)^2 +4

1 answer:

3 0

$12=2(3x-7)^2+4 \ \ \ |-4 \\
8=2(3x-7)^2 \ \ \ |\div 2 \\
4=(3x-7)^2 \\
\sqrt{4}=\sqrt{(3x-7)^2} \\
2=|3x-7| \\
3x-7=2 \ \lor \ 3x-7=-2 \\
3x=2+7 \ \lor \ 3x=-2+7 \\
3x=9 \ \lor \ 3x=5 \\
x=\frac{9}{3} \ \lor \ x=\frac{5}{3} \\
x=3 \lor \ x=1 \frac{2}{3} \\
\boxed{x \in \{1 \frac{2}{3}, 3 \} }$

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