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tino4ka555 [31]
3 years ago
11

What is the solution set for 12=2(3x - 7)^2 +4

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0
12=2(3x-7)^2+4 \ \ \ |-4 \\
8=2(3x-7)^2 \ \ \ |\div 2 \\
4=(3x-7)^2 \\
\sqrt{4}=\sqrt{(3x-7)^2} \\
2=|3x-7| \\
3x-7=2 \ \lor \ 3x-7=-2 \\
3x=2+7 \ \lor \ 3x=-2+7 \\
3x=9 \ \lor \ 3x=5 \\
x=\frac{9}{3} \ \lor \ x=\frac{5}{3} \\
x=3 \lor \ x=1 \frac{2}{3} \\
\boxed{x \in \{1 \frac{2}{3}, 3 \} }
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Answer:

length = 16 yd, width = 21 yd

Step-by-step explanation:

A= l*w

336=l*w

w=5+l

336=l*(5+l)

l²+5l-336=0

l= 16, -21

length cant be negative so

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plug l in to find w

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Which of the following is a solution of 4x + 2y ≤ 6?
cestrela7 [59]

Answer:

D. (1,0)

Step-by-step explanation:

Just plug in each coordinate for x and y into 4x+2y and see which one is less than or equal to 6.

Lets go through all of the possible answers:

<u>A</u>. (0,4)

4(0) + 2(4) ≤ 6

0 + 8 ≤ 6

8 ≤ 6

This is false.  8 is not less than or equal to 6.

<u>B</u>. (5,0)

4(5) + 2(0) ≤ 6

20 + 0 ≤ 6

20 ≤  6

This is false.  20 is not less than or equal to 6.

<u>C</u>. (5,7)

4(5) + 2(7) ≤ 6

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This is false because 35 is not less than or equal to 6

<u>D</u>. (1,0)

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6 0
3 years ago
At a certain gas station, 40% of the customers use regular gas (A1), 35% use plus gas (A2), and 25% use premium (A3). Of those c
grandymaker [24]

Answer:

a.)

P( A₂ ∩ B ) = P(B | A₂) × P(A₂)

P( A₂ ∩ B ) = 0.40 × 0.35

P( A₂ ∩ B ) = 0.14

b.)

P(B) = P( A₁ ∩ B )  + P( A₂ ∩ B ) + P( A₃ ∩ B )

P(B) = 0.08 + 0.14 + 0.125

P(B) = 0.345

c.)

For regular gas:

P(A₁ | B) = P( A₁ ∩ B ) / P(B)

P(A₁ | B) = 0.08 / 0.345

P(A₁ | B) = 0.232

For plus gas:

P(A₂ | B) = P( A₂ ∩ B ) / P(B)

P(A₂ | B) = 0.14 / 0.345

P(A₂ | B) = 0.406

For premium gas:

P(A₃ | B) = P( A₃ ∩ B ) / P(B)

P(A₃ | B) = 0.125 / 0.345

P(A₃ | B) = 0.362

Step-by-step explanation:

We are given the following information

40% of the customers use regular gas (A2)

P(A₁) = 0.40

35% use plus gas (A2)

P(A₂) = 0.35

25% use premium (A3)

P(A₃) = 0.25

Of those customers using regular gas, only 20% fill their tanks (event B).

P(B | A₁) = 0.20

Of those customers using plus, 40% fill their tanks

P(B | A₂) = 0.40

Whereas of those using premium, 50% fill their tanks.

P(B | A₃) = 0.5

a) What is the probability that the next customer will request plus gas and fill their tank?

We are asked to find P(A₂ ∩ B) = ?

Recall that Multiplicative law of probability is given by

P( A₂ ∩ B ) = P(B | A₂) × P(A₂)

P( A₂ ∩ B ) = 0.40 × 0.35

P( A₂ ∩ B ) = 0.14

b) What is the probability that the next customer fills the tank?

We are asked to find P(B) = ?

P(B) = P( A₁ ∩ B )  + P( A₂ ∩ B ) + P( A₃ ∩ B )

P( A₂ ∩ B ) is already calculated, we need to calculate

P( A₁ ∩ B ) and P( A₃ ∩ B )

So,

P( A₁ ∩ B ) = P(B | A₁) × P(A₁)

P( A₁ ∩ B ) = 0.20 × 0.40

P( A₁ ∩ B ) = 0.08

P( A₃ ∩ B ) = P(B | A₃) × P(A₃)

P( A₃ ∩ B ) = 0.50 × 0.25

P( A₃ ∩ B ) = 0.125

Finally,

P(B) = P( A₁ ∩ B )  + P( A₂ ∩ B ) + P( A₃ ∩ B )

P(B) = 0.08 + 0.14 + 0.125

P(B) = 0.345

c) If the next customer fills the tank, what is the probability that the regular gas is requested? Plus? Premium

For regular gas:

P(A₁ | B) = P( A₁ ∩ B ) / P(B)

P(A₁ | B) = 0.08 / 0.345

P(A₁ | B) = 0.232

For plus gas:

P(A₂ | B) = P( A₂ ∩ B ) / P(B)

P(A₂ | B) = 0.14 / 0.345

P(A₂ | B) = 0.406

For premium gas:

P(A₃ | B) = P( A₃ ∩ B ) / P(B)

P(A₃ | B) = 0.125 / 0.345

P(A₃ | B) = 0.362

5 0
4 years ago
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