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umka21 [38]
3 years ago
8

The area of a playground is 336 yd?. The width of the playground is 5 yd longer than its length. Find the length and width of th

e playground.
length = 21 yd, width = 16 yd

length = 26 yd, width = 21 yd

length = 16 yd, width = 21 yd

length = 21 yd, width = 26 yd
Mathematics
1 answer:
notka56 [123]3 years ago
7 0

Answer:

length = 16 yd, width = 21 yd

Step-by-step explanation:

A= l*w

336=l*w

w=5+l

336=l*(5+l)

l²+5l-336=0

l= 16, -21

length cant be negative so

l=16

plug l in to find w

w=21

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Please tell me the area to this figure and explain how you got it. (ignore the 6 and the 4)
asambeis [7]
For the triangle:
Measure base x height divided by 2
= 4 x 3 / 2
= 12 / 2
= 6 km squared

Semi Circle:
area of a circle = pi r squared
= 3.14 x 2 km squared (half of the 4km diameter)
= 3.14 x 4 (4 is 2 squared)
= 12.56 divided by 2 (since it’s half of a circle)
= 6.28 km squared

Total:
6 + 6.28 = 12.28 km squared
8 0
4 years ago
Find the equation of the line<br> Perpendicular to y=2/3x+2 and passes through the point (3,4)
Vanyuwa [196]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check firstly what's the slope of the equation above hmmmm

\bf y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (3,4)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{3}) \implies y-4=-\cfrac{3}{2}x-\cfrac{9}{2} \\\\\\ y=-\cfrac{3}{2}x-\cfrac{9}{2}+4\implies y = -\cfrac{3}{2}x-\cfrac{1}{2}

6 0
3 years ago
This is a very weird question but my mind is blankkkkkkk!!!!!
kipiarov [429]

Answer:

Step-by-step explanation:

All of that anything you want actually

6 0
3 years ago
Read 2 more answers
2 Points
Agata [3.3K]
The answer is A. True
5 0
3 years ago
Help pls I'm gonna be screwed if you don't get this pls pls pls anyone who knows math well pls help me I'm gonna cry it's over d
erica [24]

Answer:

WRONG ALL

Step-by-step explanation:

3. Should be:

- 4 \frac{7}{8}  \times  \frac{2}{3}  \\  \\  -  \frac{39}{8}  \times  \frac{2}{3}  \\  \\  \frac{ -13}{4}

4. Should be:

- 3 \frac{1}{5}  +  -  \frac{2}{3}  \\  \\  - 3 \frac{3}{15}  -  \frac{10}{15}  \\   \\ - 3 \frac{7}{15}

I hope this helps you :)

7 0
3 years ago
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