Answer:
8% probability that he or she actually has the disease
Step-by-step explanation:
We use the Bayes Theorem to solve this question.
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
If a randomly chosen person is given the test and the test comes back positive for conditionitis, what is the probability that he or she actually has the disease?
This means that:
Event A: Test comes back positive.
Event B: Having the disease.
Test coming back positive:
2% have the disease(meaning that P(B) = 0.02), and for those, the test comes positive 98% of the time. This means that 
For the 100-2 = 98% who do not have the disease, the test comes back positive 100-77 = 23% of the time.
Then
Finally:
8% probability that he or she actually has the disease
There is no solution because the lines do not intersect
The answer to your question is 11 world championships
Answer:
When f(x) is replaced by f(x+5), it will shift the parent function '5 units' to the left.
Step-by-step explanation:
- We know that when we add a number 'a' to the input of the function, it would move the parent function 'a' units to the left.
In other words, the rule is:
- f(x + a) will shift the parent function 'a units' to the left.
Given the function
Thus, when f(x) is replaced by f(x+5), it will shift the parent function '5 units' to the left.
- The effect on the graph of the linear parent function is shown in the attached diagram.
In the graph, the red line is representing the parent function f(x) and the blue line is representing the effect on the graph i.e. f(x+5).
A bakers dozen is 12 which would be $0.41 for each cookie. If you meant 13, it would be $0.38. All you have to do is divide 4.94 by the amount of cookies
