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4 years ago

What is the answer to 2/5 - 1/4

1 answer:

4 0

2/5−1/4
=2/5−1/4
=2/5+−1/4
=8/20+−5/20
=8+−5/20
=3/20(Decimal: 0.15)

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suppose Monica walks 1 kilometer every 15 minutes how many meters further can she walk in 1 hour at this new rate

zzz [600]

If Monica walks
1km...........................15min
?km............................60min
60/15=4
Monica walks 4km in 60 min(1H)
1km=1,000m
4km=4,000m in 1 hour

6 0

3 years ago

Please help with this and explain the answer.

zysi [14]

Answer:

48.06

Step-by-step explanation:

b^2+c^2=A^2

45+16=42.06

add the extra 6

3 0

3 years ago

The function v(r) 4/3 pie r to the 3rd = can be used to find the volume of air inside a basketball given its radius. What does V

umka21 [38]

Answer:

the volume of the basketball when the radius is r

Step-by-step explanation:

V(r) is a function name V and argument list (r). Often the letter of the function name is a reminder of what the function computes. Here, V is chosen as the name because it computes Volume. The function uses r (for radius) as its independent variable. That is why r is listed in parentheses next to the function name.

So, V(r) represents a function that computes the volume of a sphere with radius r.

6 0

3 years ago

Billy puts $4900 in a bank that pays 6% annually.

Maru [420]

If it's adding to the 4,900 in the bank just add the numbers to 4,900.

After 4 years. 1,176.

Year 1: 294

Year 2: 588

Year 3: 882

Year 4: 1176

Year 5: 1470

Year 6: 1764

6 0

3 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$