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4 years ago

Which statement correctly describes the expression (15)(-8)?

Mathematics

2 answers:

IrinaK [193]4 years ago

7 0

Answer:

Step-by-step explanation:

NEGATIVE TIMES POSITIVE WILL GIVE A NEGATIVE PRODUCT

Alla [95]4 years ago

4 0

Answer:

the answer is c

Step-by-step explanation:

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3 years ago

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Select the works written by Augustine of Hippo.

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4 years ago

What is an equation of the line that passes through the point (-4,-6) and is perpendicular to the line 4x+5y=25

elixir [45]

Answer:

$y = \frac{5}{4} x - 1$

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is its gradient and c is its y-intercept.

First rewrite the equation of the given line in the form of y=mx +c.

4x+5y=25

5y= -4x +25

$y = - \frac{4}{5} x + 5$

The gradient of the given line is $- \frac{4}{5}$

The product of the gradient of perpendicular lines is -1.

$( - \frac{4}{5} )(gradient \: of \: line) = - 1 \\ gradient \: of \: line = - 1 \div ( - \frac{4}{5} ) \\ gradient \: of \: line = \frac{5}{4}$

Thus, m= $\frac{5}{4}$

$y = \frac{5}{4} x + c$

Substitute a coordinate to find c.

When x= -4, y= -6,

$- 6 = \frac{5}{4} ( - 4) + c \\ - 6 = - 5 + c \\ c = 5 - 6 \\ c = - 1$

Hence, the equation of the line is

$y = \frac{5}{4} x - 1$

7 0

3 years ago

How can you find the equation of a line that is parallel/perpendicular to a given line

alexdok [17]

In the Slope-Intercept Form, m is the slope and b is the y-intercept.

<u>Finding The Equation of a Line Parallel to the Given Line:</u> Let the given line be line a and the parallel line be line b.

1) Find the slope of line a.

Example: Line a --> $y = 5x + 2$ . The slope is 5.

2) Find the y-intercept of line b.

To do this, you need to be given the coordinates of a point located on line b.

Example: The slope is 5 and the point is (2, 3), use the Slope-Intercept Formula, $y=mx+b$ ---> $3 = 5(2) + b$ . Then you solve for b.

$3 = 5(2) + b$

$3 = 10 + b$

$3 - 10 = 10 - 10 + b$

$-7 = b$ $b=-7$

The y-intercept of line b is -7

3) Finally, plugin the slope and the y-intercept into the Slope-Intercept Form.

Example: The slope of line b is 5 and the y-intercept is -7. The equation of line b is $y = 5x - 7$ .

<u>Finding The Equation of a Line Perpendicular to The Given Line:</u> Let the given line be line a and the perpendicular line be line b.

1) Find the opposite reciprocal of the slope of line a.

Example: Line a --> $y=5x+2$ . The slope is 5, to find the opposite reciprocal of the slope you use n --> $-\frac{1}{n}$ . In this case, it would be $-\frac{1}{5}$ . The opposite reciprocal of the slope of line a is $-\frac{1}{5}$ , which would be the slope of line b.

2) Find the y-intercept of line b.

To do this, you need to be given the coordinates of the point where line a and line b both intersect.

Example: The slope of line b is $-\frac{1}{5}$ and the point is (1, 7), use the Slope-Intercept Formula, $y=mx+b$ ---> $7=-\frac{1}{5}(1) + b$ . Then you solve for b.