What is the length of the diagonal of a 10cm by 15cm rectangle?

Which statement about perfect cubes is true?

Ierofanga [76]

Step-by-step explanation:

the correct answer is c

7 0

3 years ago

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Olya would like to find a way to reduce her current debt. The table below shows Olya’s monthly income, expenses and net income A

Viktor [21]

<span>b.<span>Olya could skip a month or two paying for her school loan and put the money towards her credit card debt.</span></span>

8 0

3 years ago

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Dalila earns $108.75 for workin 15 hours as a holiday helper wrapping gifts. At this rate,how much money will she earn if she wo

Elden [556K]

Your answer would be $130.50.

We can write a ratio of earnings to hours as 108.75:15. Then, to find 18 hours, we find 1 hour and multiply by 18:

108.75 : 15
÷ 15
7.25 : 1
× 18
130.5 : 18

So therefore your answer is $130.50, I hope this helps!

3 0

3 years ago

A teacher buys packs of notebooks to give to his students. The ratio of gold notebooks to red notebooks is represented in the ta

Naddika [18.5K]

Answer:

there would be 40 gold notebooks

Step-by-step explanation:

if the ratio is 5g to 3r i took the 24 red and divided it by 3 which gave me 8. I then multiplied 8 by 5 and got 40. so 40:24 is equal to 5:3

4 0

3 years ago

All athletes at the Olympic Games (OG) are tested for performance-enhancing steroid drug use. The basic Anabolic Steroid Test (A

Semenov [28]

Answer:

a ) the probability of using steroids and having a negative test is 0.5%

b) The probability of testing positive is 6.4%

c) The probability of not using steroids, given that the test is negative is 99.47%

d) No, they are not statistically indepent.

e) The probability that the athlete will either use steroids or test positive is 6.9%

Step-by-step explanation:

Let A be the event that the test result is positive and B the event that the athlete uses Steroids. We are given the following

$P(A|B) = 90%, P(A|B^c) = 2%, P(B) = 5%$

From which we deduce that

$P(A^c|B) = 10%, P(B^c) = 95%$

a) We are asked for the probability $P(A^c\cap B)$ . REcall the conditional probability formula that, given two events C,D the conditional probability $P(C|D) = \frac{P(C\cap D)}{P(D)}$ . Then we have that

$P(A^c\cap B) = P(A^c|B)P(B) = 10\% \cdot 5\%=0.5\%$ .

b) We are asked for the probability P(A). We can use the fact that given two mutually exclusive events(that is, whose intersection is empty) A,B the probability P(C) of an event is given by $P(C) = P(C|A)P(A)+P(C|B)P(B)$ . Then

$P(A) = P(A|B)P(B)+P(A|B^c)P(B^c) = 90\%\cdot5\% + 2\% \cdot 95% = 6.4\%$

c) We are asked for the probability P(B^c|A^c). Recall that $P(A|B) = \frac{P(B|A)P(A)}{P(B)}$ . Then

$P(B^c|A^c) = \frac{P(A^c|B^c)P(B^c)}{P(A^c)}= \frac{P(A^c|B^c)P(B^c)}{1-P(A)}= \frac{(1-P(A|B^c))P(B^c)}{1-P(A)}=\frac{98\%\cdot 95\%}{1-6.4\%}= 99.47\%$

d) We say that two events A,B are statistically indepent if P(A|B) = P(A). Note that from point B the probability of testing negative is 1- 6.4% = 93.6%. Since 93.6% is different from 99.47% this means that testing positive and using steroids are not statistically independent.

e) We are asked for the probability $P(A\cup B)$ . We use the following

$P(A\cupB) = P(A)+P(B)-P(A\cap B) = P(A) +P(B)-P(A|B)P(B) = 6.4\%+5\%-90\%\cdot 5\%=6.9\%$

4 0

4 years ago