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svet-max [94.6K]
3 years ago
7

The difference between a number and 8 is 11

Mathematics
2 answers:
quester [9]3 years ago
6 0

Answer:

The difference between 19 and 8 is 11.

Step-by-step explanation:

Given:

The difference between a number and 8 is 11

Find the number.

Solution:

Let the unknown number be =x

The difference between the unknown number can be written as:

x-8

We are given that the difference =11

So we can write the equation to find x as :

x-8=11

Using additive property to solve for x

Adding 8 to both sides to isolate x on one side.

x-8+8=11+8

∴ x=19

∴ The unknown number = 19

vaieri [72.5K]3 years ago
6 0

Answer:

19

Step-by-step explanation:

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Answer:

That does not make sense

Step-by-step explanation:

So i cant really help you sorry

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Troy drove 14 miles east and then 8 miles north. How far is
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The answer is 6 and that’s after it’s rounded
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Can someone help please​
Jlenok [28]

Answer:

11/8 or, 1 and 3/8

Step-by-step explanation:

First, we have to make both the denominators the same. In this case, we can multiply 3/4 by 2, to make 4, the denominator, into 8. What we do to the denominator, we must do to the numerator! So, we multiply 3 by 2, and get 6!

Now we have, 5/8 + 6/8, which equals 11/8! Which can also be simplified to 1 and 3/8 (because the numerator is larger than the denominator)

Hope this helps! :)

5 0
3 years ago
Jeans are on sale for 20% off the regular price. Which function would give you the total cost for purchasing a pair of jeans tha
DaniilM [7]

Answer:

0.8X = Final cost

Step-by-step explanation:

Given that jeans are on sale for 20% off the regular price, to determine which function would give you the total cost for purchasing a pair of jeans that costs X dollars, the following calculation must be performed:

1X = Initial cost of the jeans

20% = 0.2

1 - 0.2 = 0.8

0.8X = Final cost

3 0
3 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard
Pie

Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

This probability is the pvalue of Z when X = 30393 + 339 = 30732 subtracted by the pvalue of Z when X = 30393 - 339 = 30054. So

X = 30732

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{30732 - 30393}{472.81}

Z = 0.72

Z = 0.72 has a pvalue of 0.7642.

X = 30054

Z = \frac{X - \mu}{s}

Z = \frac{30054 - 30393}{472.81}

Z = -0.72

Z = -0.72 has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

4 0
3 years ago
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