Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
The answer is, y = -1/3 - 3
Answer:
x = 6; 6 weeks
Step-by-step explanation:
Hi!!
Okay, so here is the equation needed to solve:
85.00 = 25.00 + 12.00x
Subtract 25 from both sides
85 -25 = 25 - 25 + 12x
Then, you get:
55 = 12x
Divide 55 by 12
55/12 =x
so x = 6
Hope this helps!