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3 years ago

What percent of 360 is 90

Mathematics

2 answers:

Advocard [28]3 years ago

8 0

Answer:

90/360=.25 .25*100= 25%

Step-by-step explanation:

Anna35 [415]3 years ago

3 0

Answer:

25%

Step-by-step explanation:

90/360=.25 .25*100= 25%

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How many significant figures does 120 have

Degger [83]

Answer:

two significant figures

Step-by-step explanation:

6 0

3 years ago

Need help answering this one! -geometry

lana [24]

Answer:

Step-by-step explanation:

7 0

3 years ago

Since an instant replay system for tennis was introduced at a major tournament, men challenged 1406 referee calls, with the re

erastova [34]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for men and women players. The population proportions of men and women challenges for calls would be p1 and p2

P1 - P2 = difference in the proportion of men and women challenges for calls.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 ≠ p2

p1 - p2 ≠ 0

it is a two tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For old dough

x1 = 416

n1 = 1406

P1 = 416/1406 = 0.3

For new dough,

x2 = 217

n2 = 778

P2 = 217/778 = 0.28

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (416 + 217)/(1406 + 778) = 0.29

1 - pc = 1 - 0.29 = 0.71

z = (P1 - P2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.3 - 0.28)/√(0.29)(0.71)(1/1406 + 1/778) = 0.02/√0.00553857907

z = 0.99

Since it is a two tailed test, the curve is symmetrical. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score to the left of 0.99 is 1 - 0.84 = 0.16

We would double this area to include the area in the left tail of z = - 0.99 Thus

p = 0.16 × 2 = 0.32

Since 0.1 < 0.5, we would accept the null hypothesis.

p value = 0.337

Since 0.05 < 0.32, we would accept the null hypothesis

7 0

3 years ago

HELP ASAP PLZZZZ

Tcecarenko [31]

QUESTION 1

The given system of equations is

$3d - e = 7...eqn(1)$
$d + e = 5...eqn(2)$

To solve by linear combination, we add equation (1) to equation (2) to get,

$3d + d= 7 + 5$

$4d = 12$

We divide through by 4 to obtain,

$d = \frac{12}{4}$

$d = 3$

We put d=3 into equation (2) to get,

$3+ e = 5$

$e = 5 - 3$

$e = 2$

$\boxed {The \: solution \: is \: (3, 2)}$

QUESTION 2

The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)

To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

$4x - 3x = 5 - 3$

This implies that,

$x = 2$

Put x=3 into equation (1) to get,

$4(2) + y = 5$

$8+ y = 5$

$y = 5 - 8$

$y = - 3$

The solution is

$(2,-3)$

QUESTION 3

We want to solve the system;

a – 2b = –2 ....eqn(1)

2a + 2b = 14...eqn(2)

by linear combination.

We need to add equation (1) to equation (2) to eliminate b.

This implies that,

$2a + a = 14 + - 2$

Simplify,

$3a = 12$

Divide both sides by 3 to get,

$a = 4$
Put a=4 into equation (2) to obtain,

$2(4) + 2b = 14$

$8 + 2b = 14$
$2b = 14 - 8$

$2b = 6$

$b = 3$

The ordered pair in the form (a, b) is

$(4,3)$

QUESTION 4

The given system of equations is

11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)

We subtract equation (2) from equation (1) to get,

$11x - 3x = 18 - 2$

$8x = 16$

$x = 2$

Put x=2 into equation (2) to obtain,

$3(2) + 4y = 2$

This implies that,

$6 + 4y = 2$

$4y = 2 - 6$

$4y = - 4$

$y=-1$

The correct answer is (2,-1).

QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2

We add the two equations to eliminate e.

This implies that,

$2d + d = 8 + 4$

$3d = 12$

We divide both sides by 3 to get,

$d = 4$

We put d=4 into equation (2) to get,

$4 - e = 4$

$- e = 4 - 4$

$- e = 0$

$e = 0$

The solution is

$(4,0)$

7 0

3 years ago

Rectangle STUV has square PQRS removed, leaving an area of 92 m^2. Side PT is 4 m in length and side RV is 8m in length

Andrei [34K]

Answer:

117 $m^{2}$

Step-by-step explanation:

First think of the square that was removed. All 4 sides are equal but you don't know the length so lets gives them the variable X.

So to find the area of the rectangle, insert those variables into the area equation for a rectangle.

(RV + (X) ) (PT +(X)) = rectangle area

Now you are given what the area is if you remove the square. So subtract the the square's area from the equation above and set it equal to the size they told you.

(RV + (X)) (PT + (X)) - [(X)(X)] = 92 $m^{2}$

rectangle - square = remaining area

Now plug in the numbers you know and solve for X.

(8 + X) (4 + X) - ((X)(X)) = 92

Use FOIL to multiply the first part of the equation (first, outer, inner, last)

32 + 8x + 4x + $x^{2}$ - $x^{2}$ = 92

32 + 12x = 92

12x = 60

x = 5

So now you know the size of the square. Each side is 5m. So add 5m onto the top of the rectangle and onto the side. The top is 13m and the side is 9m. The area of the rectangle is the length times the height to 13 x 9 which is 117 $m^{2}$

6 0

2 years ago