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Akimi4 [234]
3 years ago
5

Give an example of a balance that has a greater integer value than a balance of -$12, but represents a debt of less than $5.

Mathematics
1 answer:
Orlov [11]3 years ago
5 0

Answer:

An example of a balance that has a greater integer value than a balance of -$12, but represents a debt of less than $5 is any integer belongs to [-6,-11]

Step-by-step explanation:

Let x be the balance that has a greater integer value than a balance of -$12, but represents a debt of less than $5.

We are given that a balance that has a greater integer value than a balance of -$12

So, x>-12

We are given that balance represents a debt of less than $5.

Debt = -5

So, x< -5

So, -5>x>-12

So, x∈[-6,-11]

Hence an example of a balance that has a greater integer value than a balance of -$12, but represents a debt of less than $5 is any integer belongs to [-6,-11]

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6(33 - w) = 90 solve for w entre your answer in the box w =
aliina [53]

Answer:

w = 18

Step-by-step explanation:

6(33 - w) = 90

33 - w = 15

-w = -18

w = 18

5 0
2 years ago
If the 9-inch wheel of cheese costs $18.60, what is the cost per square inch? If the cost is less than a dollar, put a zero to t
vagabundo [1.1K]

Find the area of the wheel:

Area of a circle is found using the formula:

Area = PI x r^2

9 inch would be the diameter, so the radius would be 9/2 = 4.5 inches.

The area would be 3.14 x 4.5^2 = 63.6 square inches.

Now divide the price by the area to get price per square inch:

Cost per square inch = 18.60 / 63.6 = $0.29 (rounded to the nearest cent)

5 0
4 years ago
Read 2 more answers
Helpppppppppppppp !!!
Artemon [7]

Answer:

a) 8

b) 2 1/4 hours

c) 4 7/8 hours

d) 4 1/8 hours

Step-by-step explanation:

a) LCD to be used to solve this problem is calculated as the Lowest common denominator of the above mixed fractions.

We have 1 1/2 hours and 1 1/8 hours

The lowest common denominator is the denominator calculated by

Multiplying the two denominators together and dividing by the common factor of the two denominators

Hence , we have

2 × 8 = 16

The common factor of 2 and 8 = 2

LCD = 16/2 = 8

b) How long did Matt drive?

We are told that Matt drove twice as long as John

John drove for 1 1/8 hours

Hence, the number of hours that Matt drove for =2 × 1 1/8

= 2 × 9/8 = 9/4 hours = 2 1/4 hours

c) How long the Sam, John and Matt drive ?

We are told in the question that

Sam drove for 1 1/2 hours

John drove for 1 1/8 hours

Matt drove for 2 1/4 hours

We would sum up the number of hours that each of them drove.

1 1/2 + 1 1/8 + 2 1/4

The Lowest common multiple of denominators is 8

= (1 + 1 + 2)( 4 + 1 +2/8)

= 4(7/8)

= 4 7/8 hours

d) How many hours is left for Bob to drive

We are told that the entire journey = 9 hours

The number of hours Sam, John and Matt drove for has been calculated in question c as 4 7/8 hours

The number of hours Bob will drive for is calculated as

9 hours - 4 7/8 hours

= 4 1/8 hours

6 0
3 years ago
A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.
stich3 [128]

Answer:

The distance between 12m-sides is 5\sqrt{2}m.

Step-by-step explanation:

It is given that the parallelogram has sides 10m and 12m and an angle of 45°.

Draw an altitude from one 12m side to another 12 m side as shown in below figure.

The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.

Since angle C is acute angle therefore it must be 45 degree.

\sin\theta=\frac{perpendicular}{hypotenuse}

\sin C=\frac{BE}{BC}

\sin(45^{\circ})=\frac{d}{10}

\frac{1}{\sqrt{2}}=\frac{d}{10}

\frac{10}{\sqrt{2}}=d

\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=d

\frac{10\sqrt{2}}{2}=d

5\sqrt{2}=d

Therefore the distance between 12m-sides is 5\sqrt{2}m.

4 0
3 years ago
Which is the dependent variable in 4x^2-5/6x-9=y if y=f(x)
olga55 [171]

Answer:

  y

Step-by-step explanation:

The expression

  y = f(x)

tells you that y is the dependent variable, and that it depends on x, the independent variable. The <em>independent</em> variable is always the function argument. Any variable that depends on that is the <em>dependent</em> variable.

4 0
3 years ago
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