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victus00 [196]
4 years ago
5

Battery was charged. when the charging began it was 23% full after 30 minutes of charging the battery was 89% full. how fast was

the battery charged? How long did it take the battery to be funny charged?
Mathematics
2 answers:
MrRissso [65]4 years ago
7 0
<span>The battery was charged at a rate of <span><span>2.2 </span></span>percent per minute.It took the battery <span><span>35</span></span> minutes to be fully charged.</span>
sukhopar [10]4 years ago
5 0

Answer:

The battery was charged at a rate of 2.2 % per minute.

It took 35 minutes to fully charge the battery

Step-by-step explanation:

Initial amount of charge = 23%

Charge after 30 minutes = 89%

Percentage of charge gained in 30 minutes = 89-23

                                                                         = 66 %

Charging speed of battery = \frac{percentage\hspace{3}of\hspace{3}charge\hspace{3}gained}{time\hspace{3}taken\hspace{3}in\hspace{3}minutes}

= \frac{66}{30}

= 2.2 % per minute

2.2% charge takes 1 minutes

1% charge takes \frac{1}{2.2} minutes

Initially it was 23% charged so it needs 77% more charge to be fully charged.

So, 77% charge takes \frac{1}{2.2}*77 minutes    

                         =  \frac{100}{2.2} minutes

                         = 35 minutes

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Answer:

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Step-by-step explanation:

x^2 + y^2 - 2y - 8x - 19 = 0

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3 years ago
I need help ASAP. Thank you :)
kvasek [131]

m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

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116° + m∠CBF = 180°

m∠CBF = 64°

If CD || BE, then CD || BF.

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Therefore BFCD is a parallelogam.

<em>In parallelogram, Adjacent angles form a linear pair.</em>

m∠CBF + m∠BFD = 180°

64° + m∠BFD = 180°

m∠BFD = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

m∠DFE = 64°

we know that DE ≅ DF.

<em>In triangle, angles opposite to equal sides are equal.</em>

m∠DFE = m∠DEF

m∠DEF = 64°

<em>sum of all the angles of a triangle = 180°</em>

m∠DFE + m∠DEF + m∠FDE = 180°

64° + 64° + m∠FDE = 180°

m∠FDE = 52°

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3/4/ 5/1

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