Answer:
The program required is in the explanation segment.
Explanation:
Program :
import math
# a. displays the sum of all even numbers between 2 and 100 (inclusive).
print("All even numbers from 2 to 100 inclusive ")
sum=0
i=2
while i<=100:
if i %2 ==0:
sum=sum+i
print(i,end=" ")
i=i+1
print("\nThe sum of all even numbers between 2 and 100 (inclusive) :",sum);
#b. displays the sum of all squares between 1 and 100 (inclusive).
print("\nAll squares numbers from 1 to 100 inclusive:")
i=1
sum=0
while i<=100:
print(i*i,end=" ")
i=i+1
sum=sum+(i*i)
print("\n\nThe sum of all squares between 1 and 100 (inclusive) is :",sum)
#c. displays the powers of 2 from 1 up to 256.
print("\nAll powers of 2 from 2 ** 0 to 2 ** 8:")
i=0
while True:
p=math.pow(2,i)
if p>256:
break
print("2 ** ",i," is ",int(p))
i=i+1
#d. displays the sum of all odd numbers between a and b (inclusive), where a and b are inputs
print("\nCompute the sum of all odd integers between two intgers ")
a=int(input("Enter an integer:"))
b=int(input("Enter another integer: "))
count = 0
temp=a
sum=0
while a<=b:
if a%2!=0:
print(a,end=" ")
sum=sum+a
a=a+1
print("\nThe total of the odd numbers from ", temp ," to ", b ,"is",sum)
#e.displays the sum of all odd digits of an input. (For example, if the input is 32677, the sum would be 3 + 7 + 7 = 17.)
print("\nCompute the sum of the odd digits in an integer ")
n=int(input("Enter an integer:"))
count=0
sum=0
temp=n
while n!=0:
rem = n%10
if rem%2!=0:
sum=sum+rem
count=count+1
n=int(n/10)
print("Sum of the odd digits is ",sum)
print("The total of the odd digits in ",temp," is ",count)
