Answer:
// CPP program to Convert characters
// of a string to opposite case
#include<iostream>
using namespace std;
// Function to convert characters
// of a string to opposite case
void convertOpposite(string &str)
{
int ln = str.length();
// Conversion according to ASCII values
for (int i=0; i<ln; i++)
{
if (str[i]>='a' && str[i]<='z')
//Convert lowercase to uppercase
str[i] = str[i] - 32;
else if(str[i]>='A' && str[i]<='Z')
//Convert uppercase to lowercase
str[i] = str[i] + 32;
}
}
// Driver function
int main()
{
string str = "GeEkSfOrGeEkS";
// Calling the Function
convertOpposite(str);
cout << str;
return 0;
}
Explanation:
Answer:
false
Explanation:
try to limit the amount of info on each slide
Answer:
competitive
Explanation:
An inhibitor is a substance that hinders the action of an enzyme. An inhibitor may be competitive or non competitive.
A competitive inhibitor is an inhibitor that is very similar to the substrate hence it binds to the enzyme instead of the substrate. A noncompetitive inhibitor binds to a site that is different from the active site. This site is called an allosteric site.
If we look at the experiment described in the question, the reaction rate decreases upon addition of the inhibitor. This effect is reversed by adding a large quantity of substrate.
The implication of this observation is that the enzyme and the inhibitor compete for the active site on the substrate.
Hence the inhibitor is a competitive inhibitor.
Answer:
The answer is C.) Molecules
I hope this helps! ^-^
Answer:
Following are the program in the C++ Programming Language.
#include <iostream> // header file
using namespace std; // namespace
int main() // main function
{
int n=8; //variable declaration
for(int k=n;n>=0;n-=2) // iterating over the loop to print the format
{
int n1=n;
for(int j=n1;n1>=0;n1-=2)
{
cout<<n1<<" "; // display the format
}
cout<<endl; // next line
}
return 0;
}
<u>Output</u>:
8 6 4 2 0
6 4 2 0
4 2 0
2 0
0
Explanation:
Following are the description of the program.
- Set an integer type variable "n" and initialize in it to 8.
- Set two for loop, the first loop iterate from the variable "n" that is 8 to 0 with decrement by 2 and next for loop also iterate from 8 to 0 then, print the value of the variable "n1".
- Finally, we break line after the second for loop.
