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Naya [18.7K]
3 years ago
5

Solve the equation. -4x-8=12

Mathematics
2 answers:
KIM [24]3 years ago
8 0

Steps to solve:

-4x - 8 = 12

~Add 8 to both sides

-4x = 20

~Divide -4 to both sides

x = -5

Best of Luck!

klasskru [66]3 years ago
5 0

Answer:

x=5

Step-by-step explanation:

4x−8=12

4x-8+{\color{#b14ba5}{8}}=12+{\color{#b14ba5}{8}}

4x−8+8=12+8

simplify

4x=20

divide both sides of the equation by the same term

4x=20

4

4x

​  

=  

4

20

​

the answer is

x=5

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Colt1911 [192]
2+2=4 because if you have 2 and you add another 2 you will have 4
4 0
3 years ago
Simplify <br> -4x+2x2-x2+5-3x
Serga [27]

Answer:

9 - 7x - x²

Step-by-step explanation:

-4x+2x2-x²+5-3x = -4x-3x+2x2+5-x²

I arranged the like terms together so it is easier to do the calculations.

-4x-3x+2x2+5-x² = -7x+4+5-x²

Simplify.

-7x+4+5-x² = 9-7x-x²

3 0
3 years ago
Read 2 more answers
34
Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

4 0
3 years ago
Please can you help me with questions 1-6
Maru [420]
1.) -4x-32  2.) -6x-3  3.) -3n-28  4.) -2x-7  5.) ???  6.) 4b-2    (I couldn't figure out #5 sorry)
7 0
3 years ago
Read 2 more answers
Given sin thata = 2/5 and 0° &lt; thata &lt; 90°. find sin 2 thata​
Andrej [43]

Recall the double angle identity:

\sin2\theta=2\sin\theta\cos\theta

With \theta measuring between 0º and 90º, we know \cos\theta>0. So from the Pythagorean identity, we get

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\dfrac{\sqrt{21}}5

Then

\sin2\theta=2\dfrac25\dfrac{\sqrt{21}}5=\dfrac{4\sqrt{21}}{25}

5 0
4 years ago
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