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Masja [62]
3 years ago
5

What is the additive inverse of the complex number -8+3i​

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

8-3i

Step-by-step explanation:

additive inverse of a+bi is -(a+bi)

so -(-8+3i) -- distribute negative through ()

8-3i

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What is the solution set of the compound inequality x+1<-2x+11<3x+5
VikaD [51]

Answer:

6/5 < x < 10/3 is the desired solution.

Step-by-step explanation:

Here, the given compound inequality is :

x + 1 < -2 x + 11 < 3 x + 5

Now, consider the first two term of the inequality, we get:

x + 1 < -2 x + 11

Subtracting 1 from both sides, we get:

x + 1  - 1 < -2 x + 11  - 1

or, x < -2x + 10

or, x + 2x < 10

or, 3 x < 10

or, x <  10/3

Similarly, considering the last two terms of the given inequality, we get:

-2 x + 11 < 3 x + 5

Subtracting 11 from both sides, we get:

-2 x + 11  - 11 < 3 x + 5 - 11

or, - 2 x < 3 x-6

or, 6 < 5 x

or, x > 6/5

Hence, combining two solutions, we get:    6/5 < x < 10/3

So, the desired value of x should be more than (6/5) but less than (10/3)

6 0
3 years ago
What is -2(4g-3)=30 I can't figure it out so I need so help
Sunny_sXe [5.5K]

Answer:-3

Step-by-step explanation:do the distributive property. So let's simplify it more: -8g+6=30. Minus the positive 6 to make it a zero then minus the 30 to make it a 24. -8g=24 is what's left. Divide both sides by negative 8: g= -3

4 0
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Answer:

Huh?

Step-by-step explanation:

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Write the ratios in different formats EX: a to b, a:b, and a/b
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3 years ago
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