Given:
Susan divides the fraction by .
Her friend Robyn divides by .
To find:
The quotient of Susan and Robyn.
Solution:
Susan divides the fraction by .
So, Susan's quotient is 10.
Her friend Robyn divides by .
So, Robyn's quotient is 20.
Since 20>10, therefore, Robyn will get greater quotient.
Answer:
11 cm, 11 cm
Step-by-step explanation:
Let the length and width of the rectangle be x cm and y cm respectively.
Therefore,
Perimeter of rectangle = 44 cm
2(x + y) = 44
x + y = 44/2
x + y = 22...... (1)
Area of rectangle = xy
When length is increased by 4 cm and breadth is increased by 2 cm.
New length = (x + 4) cm
New width = (y + 2) cm
New area of rectangle = original area + 72.. (given)
Therefore,
(x + 4) (y + 2) = xy + 72
xy + 2x + 4y + 8 = xy + 72
2x + 4y = 72 - 8
2x + 4y = 66
2(x + 2y) = 66
x + 2y = 66/2
x + 2y = 33.... (2)
Subtracting equation (1) from equation (2)
x + 2y - (x + y) = 33 - 22
x + 2y - x - y = 11
y = 11
Substituting y = 11 in equation (1)
x + 11 = 22
x = 22 - 11
x = 11
Thus, the dimensions of the rectangle are 11 cm and 11 cm.
-2x+1=-x^2+4
X^2 - 2X + 1 - 4 =0
X^2-2X-3=0
discriminant= (-2)^2 - 4(-3)(1)
=16
D1 = {-(-2)+√16}/2
D1=(2+4)/2
=6/2
D1=3.
D2={-(-2)-√16}/2
=(2-4)/2
=-2/2
D2= -1
the solutions are {-1 ; 3 }
so A) x= -1,3
Answer:
The distance between (9,1) to (1,8) is 3.26
Step-by-step explanation:
To solve this exercise we first have to calculate the distances between the factors of x and those of y
(x , y)
P1 = (9 , 1)
P2 = (1 , 8)
To calculate the distance we have to do P1 - P2
(9 , 1) - (1 , 8)
we subtract the corresponding from each other
9 - 1 = 8
1 - 8 = -7
(8 , -7)
Now that we have obtained these values, what we have to do is Pythagoras, since x represents a horizontal displacement, and y represents a vertical one, and the distance will be the hypotenuse that is formed from them.
h² = 8² + (-7)²
h² = 64 + 49
h² = 113
h = √113
h = 3.26
The distance between (9,1) to (1,8) is 3.26