Question

Which equation best represents a trend line for the scatter plot?

Answer 1

Answer:

Option A ic orrect.

$y=-\frac{3}{7}x+ 4$

Step-by-step explanation:

Point slope form:

The equation of line is given by:

$y-y_1=m(x-x_1)$      .....[1]

where m is the slope of line and a point $(x_1,y_1)$ lies on the line in the coordinate plane.

As per the statement:

You can see from the graph of line

We have two points i.e,

(0, 4) and (7, 1)

First calculate the slope:

$\text{Slope} = \frac{y_2-y_1}{x_2-x_1}$

then;

$\text{Slope}(m) = \frac{1-4}{7-0} = -\frac{3}{7}$

Now, substitute the value of m and (0,4) in [1] we have;

$y-4=-\frac{3}{7}(x-0)$  

Simplify:

$y-4=-\frac{3}{7}x$

Add 4 to both sides we get;

$y=-\frac{3}{7}x+ 4$

Therefore, the equation best represents the trend line for the scatter plot is $y=-\frac{3}{7}x+ 4$

Answer 2

Y = (-3/7)x + 4

Looking at the graph, you can see the trend line plotted. And conveniently, there are a couple of points on the trend line that are indicated. Those points being (0,4) and (7,1). The equation of a line in slope intercept form is:y = ax+b

Looking at the points available, the point (0,4) already gives us the y intercept since x is equal to 0. So our equation becomes:
y = ax + 4

Now we need to determine a which is the slope. The slope is the change in y divided by the change in x. So let's do that
(1-4)/(7-0) = -3/7

And now our equation becomes:
y = (-3/7)x + 4

And given formatting issues, the first option available is the correct one.