This one is best done by elimination:
We need to start 4 meters away, so B is clearly wrong.
We first move towards Mr. Wilson (i.e. distance is decreasing) so A is wrong.
Our speed is faster on the way back, so the two sloped section must have differing slopes, so D is wrong.
(D also doesn't start at 4, it's wrong for two reasons.)
Only C is left.
We can check each part to make sure. First we start at 4m, then move away, then stay still (zero slope) for three seconds, then move back faster (higher slope). All parts check out ok.
Answer:
BD does bisect the angle created by ABC, however it does not bisect segment AC. So it really depends on what you are determining the bisection to be.
Step-by-step explanation:
We can tell that it is bisecting the angle since it creates two congruent angles.
We can tell that it does not bisect the segment as AD and CD are not the same length.
In triangle ABC and DEF
AC =DF, [ given ]
AB =DE, [ given ]
angle A = angle D
by SAS
ABC congruent to triangle DFE
so
BC = EF, [ CPCTC]
hence proved
Answer:
Step-by-step explanation:
(2x + 1)(ax + b) = 6x² - 5x + c
Expand the left side and put that half into standard form:
2ax² + 2bx + ax + b = 6x² - 5x + c
2ax² + (2b + a)x + b = 6x² - 5x + c
So now look at the x terms. We have "2a" x² on left and 6 x² on right, so:
2a = 6
a = 3
Then look at the x terms, those coefficients will then be equal:
2b + a = -5
2b + 3 = -5
2b = -8
b = -4
and finally, then non-x terms are equal:
b = c
-4 = c
so:
a = 3, b = -4, c = -4
