What is the area of this polygon

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

6 0

Answer:

First find the distance between points M and V and the distance between points M and R using the distance formula:

MV = the sq. rt of (-2 - (-5)^2 + (3 - 2)^2

MV = the sq. rt of 9 + 1

MV = the sq. rt of 10

MR = the sq. rt of (-2 - (-5)^2 + (-3 - 2)^2

MR = the sq. rt of 9 + 25

MR = the sq. rt of 34

Now we cut the polygon into a triangle and a rectangle solving each area and adding them together:

Triangle- A = 1/2bh

A = 1/2(6)(3)

A = 9

Rectangle- A=bh

A = 6(5)

A = 30

Now add these areas together- 30 + 9 = 39units^2 and that's your answer

iragen [17]3 years ago

3 0

Answer:

The area of any regular polygon is given by the formula: Area = (a x p)/2, where a is the length of the apothem and p is the perimeter of the polygon. Plug the values of a and p in the formula and get the area.

Step-by-step explanation:

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Andreas93 [3]

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<h2>Explanation:</h2>

Step 1. Write $x^2 - 8x - 33=0$ in the form $x^2+2ax+a^2=0$

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Step 2. Add and subtract $(-4)^2$ to the left side of the equation

$x^2-8x-33+\left(-4\right)^2-\left(-4\right)^2=0 \\ \\ \\ But: \\ \\ x^2+2ax+a^2=\left(x+a\right)^2 \\ \\ x^2-8x+\left(-4\right)^2=\left(x-4\right)^2$

Step 3. Complete square

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