When a table is displayed in datasheet view, each column represents a select one:

Ssume that the timeout values for all three protocols

prisoha [69]

Answer:

The explanation of the question is described in the section below.

Explanation:

(a)

Go Back N :

A gives in a maximum of 9 pieces. Typically they will be sent back sections 1, 2, 3, 4, 5 and then re-sent segments 2, 3, 4 and 5.

B sends out 8 ACK's. They are 4 ACKS including 1 series and 4 ACKS with 2, 3, 4 and 5 series amounts.

Selective Repeat :

A sends in such max of 6 bits. Subsequently, segments 1, 2, 3, 4, 5 and earlier re-sent Segments 2 will be sent.

B assigns five ACKs. We are 4our ACKS with numbers 1, 3, 4, 5. However there is one sequence quantity 2 ACK.

TCP :

A assigns in a total of 6 bits. Originally, segments 1, 2, 3, 4, 5 and future re-sent Segments 2 have always been sent.

B sends five ACKs. There are 4 ACKS with either the number 2 series. There has been one ACK with a sequence of numbers 6. Remember that TCP always needs to send an ACK with a sequence number you anticipate.

(b)

This is although TCP utilizes convenient retransmission without searching for the time out.

So, it's the right answer.

4 0

3 years ago

Write a function named joinStrings() that keeps asking the user for words and joins them together. Each word should start with a

Tamiku [17]

Answer:

* The code is in Python

def joinStrings():

join = ""

while True:

str = input("Enter a word or Q to stop: ")

if str == "Q":

break

else:

join = join + " " + str

return join

print(joinStrings())

Explanation:

Create a function called joinStrings

Initialize join variable to hold the strings that will be combined

Create a while loop that stops when user enters "Q". Otherwise, ask the user for a new string and join it to the join variable with a space

When the loop is done, return the join

Call the function and print the result

4 0

3 years ago

You are given two variables, already declared and assigned values, one of type double, named price, containing the price of an o

Oksi-84 [34.3K]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

//variable to store input

double price;

int totalNumber;

// variable to store total price

double total_price;

cout<<"Enter the price of an order:";

// read the price of an order

cin>>price;

cout<<"Enter the number of orders:";

// read the total number of orders

cin>>totalNumber;

// calculate total price of all orders

total_price=price*totalNumber;

cout<<"total price of all orders: "<<total_price<<endl;

return 0;

}

Explanation:

Declare three variables "price" of double type,"totalNumber" of int type And "total_price" of type double.Read the value of an order and number of orders. The calculate the total price by multiply "price" with "totalNumber" and assign it to variable "total_price". Print the total price.

Output:

Enter the price of an order:12.5

Enter the number of orders:3

total price of all orders: 37.5

7 0

4 years ago

Which section is optional in a resume?

suter [353]

<em>Career Objectives </em>are pointless in a resume, Things like experience, Contact details, education and skills, help the company decide whether to take you or not, in accordance with their needs. They don't need to know why you want the job as opposed to how you could help them.

7 0

3 years ago

Fill in the code to complete the following method for checking whether a string is a palindrome. public static boolean isPalindr

Ilia_Sergeevich [38]

Answer:

(s.charAt(0) != s.charAt(s.length()-1))

Explanation:

public class Palindrome

{

public static void main(String[] args) {

System.out.println(isPalindrome("car"));

System.out.println(isPalindrome("carac"));

}

public static boolean isPalindrome(String s) {

if (s.length() <= 1)

return true;

else if (s.charAt(0) != s.charAt(s.length()-1))

return false;

else

return isPalindrome(s.substring(1, s.length() - 1));

}

You may see the whole code above with two test scenarios.

The part that needs to be filled is the base case that if the character at position 0 is not equal to the character at the last position in the string, that means the string is not a palindrome. (If this condition meets, it checks for the second and the one before the last position, and keeps checking)

4 0

3 years ago