Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
The code segment does not compile because the method 'reset' does not return a value that can be displayed.
A method refers to a block of that which only runs when it is called. It is permissible to pass data, referred to as parameters, into a method. Methods are used to accomplish certain actions, and they are also called functions. As per the given code segment that appears as a method in a class, it does not compile because the method named 'reset' is not returning a value that can be printed on the screen as an output.
"
<em>Complete question:</em>
Consider the following code segment, which appears in a method in a class other than password.
Password p = new Password("password");
System.out.println("The new password is " + p.reset("password"));
The code segment does not compile because _____________ .
"
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I dont think it would, but maybe you should Google it just in case.
If a client initiates the SMTP communication using an EHLO (Extended Hello) command instead of the HELO command some additional SMTP commands are often available. They are often referred to as Extended SMTP (ESMTP) commands or SMTP service extensions. Every server can have its own set of extended SMTP commands.
You go online and find the answer
