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lapo4ka [179]
3 years ago
7

3. For questions 3 and 4, write an equation and solve.

Mathematics
1 answer:
kiruha [24]3 years ago
8 0
Y decreased by 23 is 52.9....
y - 23 = 52.9 <== ur equation
y = 52.9 + 23
y = 75.9
================
c - 12 = 6 <== ur equation
c = 6 + 12
c = 18
================
h - 234 = 1192
h = 1192 + 234
h = 1426
no, he is not correct because he did not add 234 and 1192 to find the value of h, which is 1426

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∫<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bxdx%7D%7B%28x%5E%7B2%7D%2B4%29%5E%7B3%7D%20%7D" id="TexFormula1" title="\frac{xdx}{
photoshop1234 [79]

Substitute u=x^2+4 and du=2x\,dx. Then the integral transforms to

\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \int \frac{du}{u^3}

Apply the power rule.

\displaystyle \int \frac{du}{u^3} = -\dfrac1{2u^2} + C

Now put the result back in terms of x.

\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \left(-\dfrac1{2u^2} + C\right) = -\dfrac1{4u^2} + C = \boxed{-\dfrac1{4(x^2+4)^2} + C}

3 0
2 years ago
-5 2/3 + 3 1/4 + -7 1/3
alexgriva [62]
-9.5

I think I might be wrong
7 0
3 years ago
What is the product of 4+3i and 4-3i
mash [69]
Use the formula (a+b)(a-b)=a^2-b^2.

(4+3i)(4-3i)=4^2-(3i)^2=16-9i^2 \\ \\&#10;i^2=-1 \\ \\&#10;16-9i^2=16-9 \times (-1)=16+9=25 \\ \\&#10;\boxed{(4+3i)(4-3i)=25}
7 0
3 years ago
Read 2 more answers
Help me to do this question plz <br>I will make you as brainlist ​
romanna [79]

Answer:

I don't understand the language but I can do it

6 0
3 years ago
find the third,fifth and seventeenth terms of the sequence described by each explicit formula f(n)=8+3(n-1) and how you got it
alexira [117]

Answer:

Step-by-step explanation:

plug in 3 , 5 and 17 for n

8 + 3(3 -1) = 8 + 6 = 14

8 + 3(5-1) = 8 + 12 = 20

8 + 3(17-1) = 8 + 48 = 56

3 0
3 years ago
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