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Sladkaya [172]
3 years ago
13

If the relationship is proportional, what is the missing value from the table

Mathematics
1 answer:
const2013 [10]3 years ago
8 0

Answer:

the table???

lol

Step-by-step explanation:

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Please help, I’m kinda confused
iVinArrow [24]
I'm not sure, but I think is 15 :/ Hope it helped
8 0
3 years ago
Solve Using Dirac Deltla/discontinuous forcing
Jet001 [13]

Let A(t) denote the amount of salt in the tank at time t. We're told that A(0)=0.

For 0\le t\le15, the salt flows in at a rate of (1/5 lb/gal)*(5 gal/min) = 1 lb/min. When the regulating mechanism fails, 20 lbs of salt is dumped and no more salt flows for t>15. We can capture this in terms of the unit step function u(t) and Dirac delta function \delta(t) as

\text{rate in}=u(t)-u(t-15)+20\delta(t-15)

(in lb/min)

The salt from the mixed solution flows out at a rate of

\text{rate out}=\left(\dfrac{A(t)\,\mathrm{lb}}{50+(5-5)t\,\mathrm{gal}}\right)\left(5\dfrac{\rm gal}{\rm min}\right)=\dfrac A{10}\dfrac{\rm lb}{\rm min}

Then the amount of salt in the tank at time t changes according to

\dfrac{\mathrm dA}{\mathrm dt}=u(t)-u(t-15)+20\delta(t-15)-\dfrac A{10}

Let \hat A(s) denote the Laplace transform of A(t), \hat A(s)=\mathcal L_s\{A(t)\}. Take the transform of both sides to get

s\hat A(s)-A(0)=\dfrac1s-\dfrac{e^{-15s}}s+20e^{-15s}-\dfrac1{10}\hat A(s)

Solve for \hat A(s), then take the inverse of both sides.

\hat A(s)=\dfrac{\frac{10-10e^{-15s}}{s^2}+\frac{200e^{-15s}}s}{10s+1}

\implies\boxed{A(t)=10-10e^{-t/10}+\left(30e^{3/2-t/10}-10\right)u(t-15)}

7 0
4 years ago
Find the sum of the first 10 terms 0.5,0.9,1.3,1.7,..
IRINA_888 [86]

Answer:

0.5, 0.9, 1.3, 1.7, 2.1, 2.5, 2.9, 3.3, 3.7, 4.1

Now you can add them all

which is equal to 23

Step-by-step explanation:

8 0
3 years ago
12. The sum of two consecutive integers is 59. Write an
katovenus [111]

Step-by-step explanation:

Equation=>x+x+1=59

2x=58

x=29

the numbers are 29 and 30

5 0
2 years ago
Special right triangles <br><br> Find j <br><br> Thank you for any help ;)
jok3333 [9.3K]
Given b=21 and ∠β=60°,
a = 12.12436 = 7√3
j = 24.24871 = 14√3
∠α = 30° = 0.5236 rad = π/6
h = 10.5
area = 127.30573 = 147√3/2
perimeter = 57.37307
inradius = 4.43782
circumradius = 12.12436 = 7√3

Answer is
j = 24.24871 = 14√3
3 0
3 years ago
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