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rosijanka [135]
3 years ago
15

Miguel has two same size rectangles divivded into the same number of equal parts. One rectangle has 3/4 of the parts shaded, and

the other has 5/8 of the parts shaded. Into how many parts could each rectangle be divided?
Mathematics
1 answer:
ivanzaharov [21]3 years ago
6 0
Bother rectangles could be divided into 8 parts.
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y-(-2)=a(x-(-12))^2 \\  \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\  \\ y=ax^2+24ax+114a-2 \\  \\ y=x^2+24x+ \frac{114a-2}{a}

For a = 1,

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<span>The parabola whose minimum is at (−12,−2) is given by the equation y=x^2+ax+b, where a = 24 and b = 112.</span>
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4 years ago
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OleMash [197]

Answer:

Here you go

Step-by-step explanation:

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Write area or perimeter for each situation .Carpeting a floor?
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