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3 years ago

What is the value of y in the solution set of the system of linear equations shown

Mathematics

1 answer:

zaharov [31]3 years ago

4 0

The answer will be 10 because you plug in y=-×+12 in the equation 4x-2y=36. After you solve and do distributive property your new equation should be 4x+2x-24=36, then you add the like terms of 4x and 2x which will equal to 6x and your new equation should be 6x-24=36. Add 24 from both sides and your equation should be 6x=60, then you divide 60 by 6 and your final answer will be x=10 or 10

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3 years ago

Mark's father was putting in a new kitchen floor. The dimensions were 8 feet by 12 feet. If each tile was 1 square foot, how man

blondinia [14]

Answer:

96 tiles

Step-by-step explanation:

The kitchen floor is rectangular on shape.

The dimensions of the kitchen floor were 8 feet by 12 feet.

Hence, Area of a rectangle = Length × Width

Length = 8ft

Width = 12ft

Hence:

Area = 8ft × 12ft

= 96 ft²

If each tile was 1 square foot, the number of tiles he would need is

1 ft² = 1 tile

96 ft² = x

Cross Multiply

1ft² × x = 96 ft² × 1 tile

x = 96 ft² × 1 tile/1 ft²

x = 96 tiles

Therefore, Mark's father would need 96 tiles

8 0

3 years ago

The weight of potato chip bags filled by a machine at a packaging plant is normally distributed with a mean of 15.0 ounces and a

suter [353]

Answer:

97.73% of bags weigh more than 14.8 ounces.

Step-by-step explanation:

We are given that the weight of potato chip bags filled by a machine at a packaging plant is normally distributed with a mean of 15.0 ounces and a standard deviation of 0.1 ounces.

Let X = weight of potato chip bags filled by a machine

So, X ~ N( $\mu=15.0,\sigma^{2} =0.1^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{ X -\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean weight = 15.0 ounces

$\sigma$ = standard deviation = 0.1 ounces

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, percentage of bags that weigh more than 14.8 ounces is given by = P(X > 14.8 ounces)

P(X > 14.8 ounces) = P( $\frac{ X -\mu}{\sigma}$ > $\frac{14.8-15.0}{0.1}$ ) = P(Z > -2) = P(Z < 2)

= 0.9773 or 97.73%

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 in the z table which has an area of 0.9773.

Hence, 97.73% of bags weigh more than 14.8 ounces.

4 0

4 years ago