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aliina [53]
3 years ago
9

200% in decimal form

Mathematics
1 answer:
amm18123 years ago
7 0
For this question you should know that 200% is equal to 200/100 so the decimal will be 2 :)))
i hope this is helpful 
have a nice day 
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What is <br> 25% * 1.5 in a fraction
BlackZzzverrR [31]

Answer:

3/8

Step-by-step explanation:

If ive read this correctly it's asking what is 25% times 1.5, that would be 0.25 times 1.5 which is 0.375 turned into a fraction could be 375/1000 or simplified would be 3/8 as both are divisable by 125.

3 0
3 years ago
How do you turn 28/15 into a mixed number
Bond [772]
\frac{28}{15}  =  \frac{15 + 13}{15}  =  \frac{15}{15}  +  \frac{13}{15}  = 1 +  \frac{13}{15}  = 1 \frac{13}{15}
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20 POINTS IF YOU SOLVE!
bonufazy [111]
Question 1: D

Question 2: D

Question 3: C

Question 4: A

Question 5: D
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Assuming that workers' salaries in your company are uniformly distributed between $15,000 and $40,000 per year, find the probabi
lord [1]

Answer:

The  probability is  P(\$20,000 <  X < \$35,000) =  0.6

Step-by-step explanation:

From the question we are told that

     Workers' salaries in your company are uniformly distributed between $15,000 and $40,000 per year

  Generally the probability that a randomly chosen worker earns an annual salary between $20,000 and $35,000 is mathematically represented as

        P(\$20,000 <  X  \$35,000) =  \frac{ 35000 -  20000}{ 40000 - 150000}

  => P(\$20,000 <  X < \$35,000) =  0.6

     

3 0
4 years ago
Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100 and a standard deviation sigma equa
aleksley [76]

Answer: 0.5467

Step-by-step explanation:

We assume that the test scores for adults are normally distributed with

Mean : \mu=100

Standard deviation : \sigma=20

Sample size : = 50

Let x be the random variable that represents the IQ test scores for adults.

Z-score : z=\dfrac{x-\mu}{\sigma}

For x =85

z=\dfrac{85-100}{20}\approx-0.75

For x =115                                                                                                                                            

z=\dfrac{115-100}{20}\approx0.75

By using standard normal distribution table , the probability the mean of the sample is between 95 and 105 :-

P(85

Hence, the probability that a randomly selected adult has an IQ between 85 and 115 =0.5467

7 0
3 years ago
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