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Yuri [45]
3 years ago
15

For

middle" class="latex-formula"> and g(x) = x^{2}  -5 find (f ° g)(4)
Mathematics
2 answers:
Kamila [148]3 years ago
3 0

\bf \begin{cases} f(x)=4x+1\\ g(x)=x^2-5\\[-0.5em] \hrulefill\\ (f\circ g)(4)=f(~~g(4)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ g(4)=(4)^2-5\implies g(4)=16-5\implies \boxed{g(4)=11} \\\\\\ f(~~g(4)~~)\implies f(11)\implies f(11)=4(11)+1\implies \blacktriangleright f(11)=45\blacktriangleleft

ddd [48]3 years ago
3 0

Answer:

(f ° g)(4) = 45

Step-by-step explanation:

f(x) = 4x+1 and g(x) = x^{2}  -5 find (f ° g)(4)

"( f o g)(x)" means " f (g(x))"

That is, you plug something in for x, then you plug that value into g, simplify, and then plug the result into  f.

f(g(x)) put x = 4 in g(x) = x² - 5

g(4) = 4² - 5 = 16 - 5 = 11

now put this g(x) = 11 where x = 4 in f(g(x)) = 4x + 1

f(g(4)) = f(11) = 4(11) + 1 = 44+1 = 45

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1 hr = 7.51


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Step-by-step explanation:

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2 years ago
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Irina18 [472]

The sign of "b" on the numerator should be negative. So we conclude that the correct option is false.

<h3>Is the equation in the image correct or incorrect?</h3>

For a quadratic equation of the form:

y = a*x^2 + b*x + c

By using the Bhaskara's formula, the solutions of the equation:

0 = a*x^2 + b*x + c

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x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}

Notice that the sign of the first term on the numerator should be negative, while on the image it is positive.

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8 0
3 years ago
Please help me, I know it’s not the first one but I think it’s the last one. Can somebody please confirm or deny?
GaryK [48]

Answer:

B. 2.2π m² : 3.2π m²

Step-by-step explanation:

Given:

Slant height (l) = 2.2 m

Diameter (d) = 2 m

Radius (r) = ½(2) = 1 m

Required:

Lateral area and surface area

Solution:

✔️Formula for lateral area of a cone = πrl

Plug in the values

Lateral area of the cone = π*1*2.2

Lateral area = 2.2π m²

✔️ Formula for surface area of a cone = πr(l + r)

Plug in the values

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Surface area = 3.2π m²

The answer would therefore be:

2.2π m² : 3.2π m²

7 0
2 years ago
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