Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
-3
Step-by-step explanation:
we khow that the vertex form of a function is written this way :
f(x)=a(x-h)²+k
- the coordinates of the vertex are (h,k) so from the graph we can deduce that k = -3
Here is your answer
A. 1,3,5,7,9,11,.....
REASON :
In an AP their is a common difference between two consecutive terms.
i.e. t2-t1=t3-t2=t4-t3=....= constant
The option A satisfies above condition.
HOPE IT IS USEFUL
2.5*7 = 17.5. If it's easier for you, multiply 2.5 by 5 then add 2.5*2.
