Answer:
Step-by-step explanation:
We need a system of equations here. The first equation is that 3L boxes + 5s boxes (L = large and s = small) = 88 kg so
3L + 5s = 88
12L + 2s = 235 according to the other information given.
Solve the first equation for either L or s. I'll solve for L, just because:
3L = 88 - 5s and
L = 
and sub that into the second equation for L:
and if you distribute the 12 into the parenthesis you'll simplify it down a bit to
352 - 20s + 2s = 235 and combine like terms:
-18s= -117 so
s = 6.5 kg and plug that in to solve for L:
L = 
and
L = 18.5 kg
Answer:
25%
Step-by-step explanation:
Height of all the bars in chart = 2 or more is 10, 3, 1.
Add all the bars to give us exact amount of data required = 10 + 3 + 1 = 14
Total number of students in class = 56
Percentage of class having two or more student = (14/56) * 100% = 25%
Answer:
Step-by-step explanation:
larger rectangle:
22 x 12 = 264
to find unlabeled rectangle:
18 - 12 = 6
22 - 15 = 7
6 x 7 = 42
total area:
264 + 42 = 306
306/16.25 = 18.83
you can't buy 18.83 cases, so you round up and buy 19
We will use the right Riemann sum. We can break this integral in two parts.
We take the interval and we divide it n times:
The area of the i-th rectangle in the right Riemann sum is:
For the first part of our integral we have:
For the second part we have:
We can now put it all together:
![\sum_{i=1}^{i=n} [(\Delta x)^4 i^3-6(\Delta x)^2i]\\\sum_{i=1}^{i=n}[ (\frac{3}{n})^4 i^3-6(\frac{3}{n})^2i]\\ \sum_{i=1}^{i=n}(\frac{3}{n})^2i[(\frac{3}{n})^2 i^2-6]](https://tex.z-dn.net/?f=%5Csum_%7Bi%3D1%7D%5E%7Bi%3Dn%7D%20%5B%28%5CDelta%20x%29%5E4%20i%5E3-6%28%5CDelta%20x%29%5E2i%5D%5C%5C%5Csum_%7Bi%3D1%7D%5E%7Bi%3Dn%7D%5B%20%28%5Cfrac%7B3%7D%7Bn%7D%29%5E4%20i%5E3-6%28%5Cfrac%7B3%7D%7Bn%7D%29%5E2i%5D%5C%5C%0A%5Csum_%7Bi%3D1%7D%5E%7Bi%3Dn%7D%28%5Cfrac%7B3%7D%7Bn%7D%29%5E2i%5B%28%5Cfrac%7B3%7D%7Bn%7D%29%5E2%20i%5E2-6%5D)
We can also write n-th partial sum:
