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Answer:
Step-by-step explanation:
Given
One-eighth times three-elevenths
Required
Solve
One-eighth means 1/8
Three-elevenths means 3/11
So, mathematically; the above expression is represented as thus:
To solve this, we simply multiply the numerator and the denominator together.
After multiplying these together, the next is to check if the resulting can be simplified
If yes,we simplify it and if otherwise, we live it like that.
So,
At this point, the fraction can't be simplified any further.
Hence,
The answer is (C). All sides and angles of the square is equal. Its diagonals bisect each other and meet at 90°. If two lines are said to meet at 90°, these lines are perpendicular to each other. Therefore, the diagonals of a square is perpendicular to each other
It is false that the midpoint is in quadrant IV
<h3>How to determine the midpoint location?</h3>
The endpoints are given as:
S (1,4) and T (5,2
The midpoint is
(x, y) = 0.5 *(x1 + x2, y1 + y2)
So, we have:
(x, y) = 0.5 *(1 + 5, 4 + 2)
Evaluate the expression
(x, y) = (3, 3)
The point (3, 3) is located in the first quadrant
Hence, it is false that the midpoint is in quadrant IV
Read more about quadrants at:
brainly.com/question/7196312
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if the diameter of a circle is 15, its radius is half that or 7.5.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7.5 \end{cases} A=\pi (7.5)^2\implies A=56.25\pi \implies \stackrel{\pi =3.14}{A=176.625}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7.5%20%5Cend%7Bcases%7D%20A%3D%5Cpi%20%287.5%29%5E2%5Cimplies%20A%3D56.25%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7BA%3D176.625%7D%20)
