1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aniked [119]
4 years ago
13

Gelisa sets a goal of running between 32 and 35 miles this week. she ran 4 1/2 each morning, monday through friday. how many mil

es could gelisa run this weekend and stay within the limits of her goal?
a-9 miles
b-11 miles
c-13 miles
d- 15 miles
Mathematics
1 answer:
9966 [12]4 years ago
5 0
B- 11 miles
4.5 • 5 = 22.5
32- 22.5 = 9.5, a is not enough
35- 22.5 = 12.5, c & d are too high
You might be interested in
Help!! -4x=36 and pls show the work! thank youu
IRINA_888 [86]

Answer:

x=-9

Step-by-step explanation:

x=36/-4=-9

8 0
3 years ago
Read 2 more answers
Someone please help fast, I am really lost with the law of logarithms and need help with these questions in picture
telo118 [61]

We'll use the following log rules

  • Log rule 1:  log(xy) = log(x)+log(y)
  • Log rule 2: log(x/y) = log(x)-log(y)
  • Log rule 3: log(x^y) = y*log(x)

================================================

Part 1

<h3>Answer: 2a + 2c</h3>

-------------

Work Shown:

Ln(100) = Ln(4*25)

Ln(100) = Ln(2*2*5*5)

Ln(100) = Ln(2)+Ln(2)+Ln(5)+Ln(5) ... using log rule 1

Ln(100) = a+a+c+c

Ln(100) = 2a + 2c

================================================

Part 2

<h3>Answer: 2a + b - c</h3>

-------------

Work Shown:

Ln(2.4) = Ln(24/10)

Ln(2.4) = Ln[ (2*2*2*3)/(2*5) ]

Ln(2.4) = Ln[ (2*2*3)/5 ]

Ln(2.4) = Ln(2*2*3) - Ln(5) ... using log rule 2

Ln(2.4) = Ln(2)+Ln(2)+Ln(3) - Ln(5) .... using log rule 1

Ln(2.4) = a+a+b-c

Ln(2.4) = 2a+b-c

================================================

Part 3

<h3>Answer: -3a + b - 3c</h3>

-------------

Work Shown:

Ln(0.003) = Ln(3/1000)

Ln(0.003) = Ln[ 3/( 10^3) ]

Ln(0.003) = Ln(3) - Ln(10^3) ... log rule 2

Ln(0.003) = Ln(3) - 3*Ln(10) ... log rule 3

Ln(0.003) = Ln(3) - 3*Ln(2*5)

Ln(0.003) = Ln(3) - 3*( Ln(2) + Ln(5) ) ... log rule 1

Ln(0.003) = b - 3*( a + c )

Ln(0.003) = b - 3a - 3c

Ln(0.003) = -3a + b - 3c

================================================

Part 4

<h3>Answer: 3a + 3b + 2c</h3>

-------------

Work Shown:

All logs shown for this part are in base 2

log(5400) = log(54*100)

log(5400) = log(6*9*4*25)

log(5400) = log(2*3*3*3*2*2*5*5)

log(5400) = log(2^3*3^3*5^2)

log(5400) = log(2^3)+log(3^3)+log(5^2) ... log rule 1

log(5400) = 3*log(2)+3*log(3)+2*log(5) ... log rule 3

log(5400) = 3a + 3b + 2c

8 0
3 years ago
n 5 years, Dad will be three times as old as his daughter Jill will be then. If the sum of their present ages is 50, how old are
lara31 [8.8K]

Answer: 150


Step-by-step explanation: you have to multiply 50 and 3 and the answer is 150


7 0
3 years ago
How many times can 8 go into 60
VikaD [51]
7 times......................
4 0
4 years ago
Read 2 more answers
I need help with 45 and 48
Nuetrik [128]

Answer:

Answer 93

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • How can you do 461 divided by 3 the old school way
    13·1 answer
  • Owning a home may allow you to deduct _____.
    10·2 answers
  • What is 7/12 - 1/3?
    5·2 answers
  • Consider the sequence:
    6·2 answers
  • What is the quotient? Negative StartFraction 3 over 8 EndFraction divided by negative one-fourth
    15·1 answer
  • Three decimals between 16.4 and 16.5
    7·1 answer
  • Which is a unit rate?
    13·1 answer
  • Given an initial quantity Q0=150 and a growth rate of 7% per unit time, give a formula for the quantity Q as a function of time
    11·1 answer
  • volusia instructure.com - Private A triangle is shown below. What are the coordinates of the three vertices? 10T 9 8 -6 5 B 3 4
    13·1 answer
  • The line plot below shows the number of juice boxes Leon drank on specific days. Which three dates did Leon drink ten juice boxe
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!