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3 years ago

How many inches did the height of the plant increase between weeks 3 and 4?

Mathematics

2 answers:

Iteru [2.4K]3 years ago

8 0

The plant increased a total of 4 inches.

Week 3, the plant was 8in and week 4, the plant was 12in.

To find our solution, subtract 8 from 12

12-8=4

Alchen [17]3 years ago

8 0

Answer:

<h2>The plant grew 8 inches between week 3 and week 4.</h2>

Step-by-step explanation:

From the given graph we observe that in week 3, the plant had 8 inches height, and in the week4, the plant had 12 inches height.

To know how much grew the plant, we just have to find the variation, which is the difference:

12in - 4in = 8 in.

Therefore, the plant grew 8 inches between week 3 and week 4.

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Mariana solved the equation below. Identify her ERROR and EXPLAIN what she did wrong. -3(2x-4)=-12 -6x-12=-12 -6x=0 x=0

nydimaria [60]

Answer:

Her error was multiplying -3 and -4 which gives +12 but she wrote -12 instead

Step-by-step explanation:

Mariana workings:

-3(2x - 4) = -12

-6x - 12 = -12

Her error was multiplying -3 and -4 which gives +12 but she wrote -12 instead

-6x = 0

x=0

Correct workings:

-3(2x - 4) = -12

-6x + 12 = - 12

-6x = -12 - 12

-6x = -24

x = -24/-6

x = 4

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3 years ago

Joe wants to calculate 12×8 in a calculater but the 8 key isnt working.Explain what can he do

eduard

Answer:

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Step-by-step explanation:

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4 years ago

Read 2 more answers

An economist is interested in studying the spending habits of consumers in a particular region. The population standard deviatio

Lena [83]

Answer:

The width is $w = \$ 729.7$

Step-by-step explanation:

From the question we are told that

The population standard deviation is $\sigma = \% 1,000$

The sample size is $n = 50$

The sample mean is $\= x = \$ 15,000$

Given that the confidence level is 99% then the level of significance is mathematically represented as

$\alpha = 100 - 99$

=> $\alpha = 1\%$

=> $\alpha = 0.01$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = Z_{\frac{0.01 }{2} } = 2.58$

Generally margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} * \frac{\sigma }{\sqrt{n} }$

substituting values

$E = 2.58 * \frac{1000 }{\sqrt{50} }$

$E = 364.9$

The width of the 99% confidence interval is mathematically evaluated as

$w = 2 * E$

substituting values

$w = 2 * 364.9$

$w = \$ 729.7$

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3 years ago