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nydimaria [60]
4 years ago
15

Show that the given general solution satisfies the given differential equation, showing all work carefully. Do NOT do this by so

lving the given differential equation, but rather prove that the whole general solution makes the equation true.
DE= x^2y''- 8xy +8y=16
Gen. Sol y=c1x+c2x^8+2
Mathematics
1 answer:
shepuryov [24]4 years ago
4 0

Explanation:

Differentiating the solution, we have ...

  y' = c1 +8c2x^7

  y'' = 56c2x^6

Putting this into the DE, we have ...

  x^2y'' -8xy' +8y = 16 . . . . . . . different from your problem statement

  x^2(56c2x^6) -8x(c1 +8c2x^7) +8(c1x +c2x^8 +2) = 16

  56c2x^8 -8c1x -64c2x^8 +8c1x +8c2x^8 +16 = 16

  x^8(56c2 -64c2 +8c2) +x(-8c1 +8c1) +16 = 16

  0 +16 = 16 . . . . QED

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587×6543÷285{32+65}= ? HELP
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Step-by-step explanation:

Follow BEDMAS (brackets first, then exponents, then multiplication and division, then addition and subtraction)

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2 years ago
shakira invests $500000 at 5% compound intwerest per annum . calculate how many years it takes for the value to double in value?
Kay [80]

Answer:

t=14.2\ years    

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

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r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=?\ years\\ P=\$500,000\\ r=0.05\\n=1\\ A=\$1,000,000  

substitute in the formula above  and solve for t

1,000,000=500,000(1+\frac{0.05}{1})^{(1)t}

2=(1.05})^{t}  

Apply log both sides

log(2)=log[(1.05})^{t}]  

log(2)=(t)log(1.05)  

t=log(2)/log(1.05)  

t=14.2\ years          

8 0
3 years ago
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