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nydimaria [60]
3 years ago
15

Show that the given general solution satisfies the given differential equation, showing all work carefully. Do NOT do this by so

lving the given differential equation, but rather prove that the whole general solution makes the equation true.
DE= x^2y''- 8xy +8y=16
Gen. Sol y=c1x+c2x^8+2
Mathematics
1 answer:
shepuryov [24]3 years ago
4 0

Explanation:

Differentiating the solution, we have ...

  y' = c1 +8c2x^7

  y'' = 56c2x^6

Putting this into the DE, we have ...

  x^2y'' -8xy' +8y = 16 . . . . . . . different from your problem statement

  x^2(56c2x^6) -8x(c1 +8c2x^7) +8(c1x +c2x^8 +2) = 16

  56c2x^8 -8c1x -64c2x^8 +8c1x +8c2x^8 +16 = 16

  x^8(56c2 -64c2 +8c2) +x(-8c1 +8c1) +16 = 16

  0 +16 = 16 . . . . QED

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4 years ago
10 - 5 / 10 ^ 2 + 0.4 (4+0.2)​
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parenthesis, exponents, mult/division, add/subtract

parenthesis: 4+0.2= 4.2

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multiply/divide: 10-(1/20)×.4×4.2

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3 0
4 years ago
Find the length of the segment. Round your answer to the nearest tenth. ​
Diano4ka-milaya [45]

Answer:

The length of the line segment: 5.8 units

Step-by-step explanation:

To find the length of a line segment, you must us the formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

1. well, you must first identify your coordinates

Point A is (-2, -4) which is (x_1, y_1)

Point B is (1, 1) which is (x_2, y_2)

2. Now you put these coordinates into your equation

D=\sqrt{(1--2)^2+(1--4)^2}

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3. simplify

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4. Round it to the nearest tenth

5.83 and since 3 is lower than five, it does nothing

5.8= The length of your line segment!

4 0
3 years ago
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