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4 years ago

99 points

Mathematics

2 answers:

expeople1 [14]4 years ago

7 0

Its 54m^2 hope this helps
~Rosy67

Scrat [10]4 years ago

3 0

$l \ equal \ 3m \\\\ therefore, 6 *L^2=6*3^2 = (6*9)$

$((6*9)) = 54m^2$

<span>27 m²
30 m²
36 m²
54 m²</span>

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Which best describes the resulting three-dimensional figure? a cone with a base radius of 26 cm a cone with a base radius of 14

hammer [34]

The best description of the resulting three-dimensional figure when the considered figure is revolved is: A cylinder with height 24 cm.

<h3>What is solid of revolution?</h3>

When a figure is revolved around some fixed axis, the whole three dimensional solid formed from the area that it swaps out is called solid of revolution.

Since no image is specified, we will work on the image attached below.

We can visualize and imagine that the horizontal line is still and just rotating on its place. The rectangle will revolve around, and therefore will swap out a cylindrical shape.

Since the length of the rectangle is 24 cm, and it is rotated on its length, so that will serve as height of the formed cylinder.

Thus, the best description of the resulting three-dimensional figure when the considered figure is revolved is: A cylinder with height 24 cm.

Learn more about solid of revolution here:

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2 years ago

4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ

galben [10]

Answer:

$\\ \mu = 118\;grams\;and\;\sigma=30\;grams$

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find $\\ \mu\;and\;\sigma$ .

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

$\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}$

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

$\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}$

$\\ 2.4 = \frac{190-\mu}{\sigma}$ (2)

<h3>Solving a system of equations for values of the mean and standard deviation</h3>

Having equations (1) and (2), we can form a system of two equations and two unknowns values:

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

$\\ 2.4 = \frac{190-\mu}{\sigma}$ (2)

Rearranging these two equations:

$\\ -0.6*\sigma = 100-\mu$ (1)

$\\ 2.4*\sigma = 190-\mu$ (2)

To solve this system of equations, we can multiply (1) by -1, and them sum the two resulting equation:

$\\ 0.6*\sigma = -100+\mu$ (1)

$\\ 2.4*\sigma = 190-\mu$ (2)

Summing both equations, we obtain the following equation:

$\\ 3.0*\sigma = 90$

Then

$\\ \sigma = \frac{90}{3.0} = 30$

To find the value of the mean, we need to substitute the value obtained for the standard deviation in equation (2):

$\\ 2.4*30 = 190-\mu$ (2)

$\\ 2.4*30 - 190 = -\mu$

$\\ -2.4*30 + 190 = \mu$

$\\ \mu = 118$

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3 years ago

Three cylinders have bases that are the

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Is this a algebra question? I just want to know?

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