<h3>
Answer:</h3>
- interior: 144°
- exterior: 36°
<h3>
Step-by-step explanation:</h3>
It may be easiest to remember that the sum of exterior angles of any convex polygon is always 360°.
Your decagon has a sum of exterior angles that is 360°. Since it is a regular 10-sided polygon, each one is 1/10 that value: 36°.
The measure of each exterior angle is 36°.
The measure of an interior angle is the supplement of the exterior angle. Each interior angle of the regular 10-sided polygon will be ...
... 180° -36° = 144°
The measure of each interior angle is 144°.
_____
A formula often used for the sum of the measures of the interior angles is ...
... interior angle total = (n -2)×180°
For a 10-sided figure, the interior angle total is ...
... (10 -2)×180° = 1440°
When this sum is divided into 10 equal angles, the measure of one interior angle is ...
... 1440°/10 = 144° . . . . . agrees with the above computation
The exterior angle measure is the supplement of this:
... 180° -144° = 36° . . . . . exterior angle measure; agrees with the above computation
It is true due to the commutative property of multiplication. If all of your operations are multiplication, then the integers can move around and you can still get the same answer.
^This is only true if you meant to type (1.8x3)x2.1=(1.8x2.1)x3
If you meant what you typed, then the equation is false. The left side would be 3 times the value of the right side due to the 3 being on the left side and not the right side while without the 3 the two sides would be equal.
Answer:
x = 2y + 6
Step-by-step explanation:
-x + 2y = -6
-x = -6 - 2y
x= 6 + 2y
x = 2y + 6
Answer:
(X+10)(X-3)
Step-by-step explanation:
Answer:
A)
B)
Step-by-step explanation:
<em>x</em> and <em>y</em> are differentiable functions of <em>t, </em>and we are given the equation:
First, let's differentiate both sides of the equation with respect to <em>t</em>. So:
![\displaystyle \frac{d}{dt}\left[xy\right]=\frac{d}{dt}[6]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bxy%5Cright%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B6%5D)
By the Product Rule and rewriting:
![\displaystyle \frac{d}{dt}[x(t)]y+x\frac{d}{dt}[y(t)]=0](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdt%7D%5Bx%28t%29%5Dy%2Bx%5Cfrac%7Bd%7D%7Bdt%7D%5By%28t%29%5D%3D0)
Therefore:
A)
We want to find dy/dt when <em>x</em> = 4 and dx/dt = 11.
Using our original equation, find <em>y</em> when <em>x</em> = 4:
Therefore:
Solve for dy/dt:
B)
We want to find dx/dt when <em>x</em> = 1 and dy/dt = -9.
Again, using our original equation, find <em>y</em> when <em>x</em> = 1:
Therefore:
Solve for dx/dt:
