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victus00 [196]
3 years ago
5

In ΔRST, s = 89 inches, ∠R=63° and ∠S=92°. Find the area of ΔRST, to the nearest 10th of an square inch.

Mathematics
2 answers:
Reptile [31]3 years ago
6 0

Answer:

=720^2

Step-by-step explanation:

Vinil7 [7]3 years ago
5 0

Answer:

187.7inches^2

Step-by-step explanation:

187.738

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Diano4ka-milaya [45]

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Yes, I believe that is correct. I may be wrong.

Step-by-step explanation:

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Arnold took a tray of cookies to a party 90% of the cookies were eating only these 5 remain
e-lub [12.9K]

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50 in total, 45 were eaten

Step-by-step explanation:

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8 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}

6 0
3 years ago
A graph of the whole numbers is drawn on the number line. Which of the following points is not included on the graph? A. -1) B.
Olenka [21]
The answer to the question is c
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3 years ago
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