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4 years ago

What is the value of 5 in 356,039,763

1 answer:

7 0

Well, we know the last three numbers are:

3 (ones)
6 (tens)
7 (hundreds)

The next set is:

9 (thousands)
3 (ten thousands)
0 (hundred thousands)

And finally:

6 (millions)
5 (ten millions)
6 (hundred millions)

So we know that 5 is in ten millions.

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Helppppp plssss I’ll make brainliest

MrMuchimi

Answer:

C. 3x=21

x=7

Step-by-step explanation:

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3 years ago

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simple random sample from a population with a normal distribution of 99 body temperatures has x overbarequals98.20degrees Upper

Verizon [17]

Answer:

Step-by-step explanation:

Let x be the normal body temperature

X is N(99, sigma)

Sample mean x bar = 98.2 and s = 0.63

Margin of error = Z critical * 0.63 = 1.95 *0.63 = 1.2285

It is safe since 1.5 <1.96 critical value of z at 95%

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3 years ago

A rectangular prism has a length of 4 1/4 in., a width of 3 in., and a height of 1 1/4 in.

labwork [276]

B because 4.25 (decimals are easier for me) then you times by 3=12.75
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3 years ago

Ac is tangent to circle O at A. The diagram is not drawn to scale. If m by=52 degrees what is m yac?

Burka [1]

Answer:

Step-by-step explanation:

38°

<BAY=52°

<YAC+<BAY=90°

<YAC= 38°

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3 years ago

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Assuming boys and girls are equally likely, find the probability of a couple having a baby girl when their sixth child is born

Ivanshal [37]

Answer: The required probability of having 6th girl is 0.5.

Step-by-step explanation: Given that boys and girls are equally likely.

We are to find the probability of a couple having a baby girl when their sixth child is born, given that the first five children were all girls.

Since the events of having a boy and a girl are independent of each other, so

the probability of having 6th girl dose not depend on the birth of the first five girls.

We know that there are only two possible cases (either a boy or girl will born).

So, sample space, S = {G, B} and the event E of having a girl is, E = {G}.

That is, n(S) = 2 and n(E) = 1.

Therefore, the probability of event E is given by

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{1}{2}=0.5.$

Thus, the required probability of having 6th girl is 0.5.

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3 years ago