This pre-image was translated 3 units right and 6 units up. Use the segment tool to draw the image.
2 answers:
Answer:
We are given a pre-image now it is given that the pre-image is translated 3 units right and 6 units up so the change or the rule of the transformation in the coordinates is given by:
(x,y) → (x+3,y+6)
We are given the vertices of the pre-image are:
(-5,-4) , (-1,-6) and (1,-3)
Hence, the transformed image has the vertices aS:
(-5,-4) → (-5+3,-4+6)=(-2,2)
(-1,-6) → (-1+3,-6+6)=(2,0)
and (1,-3) → (1+3,-3+6)=(4,3)
so, the image after translation of the pre-image has vertices:
(-2,2) , (2,0) and (4,3)
Let
A( -5,-4) B(-1,-6) C(1,-3)
we know that
the rule of the transformation is
(x,y)---------> (x+3,y+6)
so
<u>Find A'</u>
(-5,-4)---------> (-5+3,-4+6)-------> A' (-2,2)
<u>Find B'</u>
(-1,-6)---------> (-1+3,-6+6)-------> B' (2,0)
<u>Find C'</u>
(1,-3)---------> (1+3,-3+6)-------> C' (4,3)
the answer in the attached figure
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The graph of linear equation 2x - 3y = -12 is as shown below.
I this question, we have been given a linear equation 2x - 3y = -12
We need to graph the points.
For x = 1,
2(1) - 3y = -12
2 - 3y = -12
-3y = -14
y = 14/3
For x = 0,
2(0) - 3y = -12
y = (-12)/(-3)
y = 4
For x = -1,
2(-1) - 3y = -12
-3y = -12 + 2
y = (-10) / (-3)
y = 10/3
So, we get coordinates (1, 14/3), (0, 4) and (-1, 10/3)
Now we plot these points.
The graph of linear equation 2x - 3y = -12 is as shown below.
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