3 years ago

Can anyone help me to solve these 2 questions please I need very clear steps !!!!

Mathematics

1 answer:

DochEvi [55]3 years ago

4 0

Hope this helps you

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How many quarts of a 50% solution of acid must be added to 20 quarts of a 20% solution of acid to obtain a mixture containing a

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Answer:

40 quarts.

Step-by-step explanation:

Let x =quarts of the 50% solution

so, according to the question

the typical mixture equivalent equation will be like this

$.50x + .20(20) = .40(x+20)\\.50x + 4 = .40x + 8\\.50x - .40x = 8 - 4\\.10x = 4\\x = 4/.10 \\x = 40$

so the answer will be 40 quarts of 50% solution should be added.

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Given f(x)=-4x-2 solve for x when f(x)=6

Paladinen [302]

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Step-by-step explanation:

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2 years ago

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MrRissso [65]

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Step-by-step explanation:

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