1. X less than of equal to (<_) -10
2. 2y > -5/2
The range of frequency is from 0.05 to 0.35 and a couple f the numbers aren't close to the other numbers 0.05 is not close to 0.21 or 0.35
so the outcomes do not appear to be equally likely, because of that a uniform probability model wouldn't be a good model.
The answer is A
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Answer:
m∠K = 37° and n = 31
Step-by-step explanation:
A lot of math is about matching patterns. Here, the two patterns we want to match are different versions of the same Law of Cosines relation:
- a² = b² +c² -2bc·cos(A)
- k² = 31² +53² -2·31·53·cos(37°)
<h3>Comparison</h3>
Comparing the two equations, we note these correspondences:
Comparing these values to the given information, we see that ...
- KN = c = 53 . . . . . . . . . . matching values 53
- NM = a = k . . . . . . . . . . . matching values k
- KM = b = n = 31 . . . . . . . matching values 31
- ∠K = ∠A = 37° . . . . . . . matching side/angle names
Abby apparently knew that ∠K = 37° and n = 31.
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<em>Additional comment</em>
Side and angle naming for the Law of Sines and the Law of Cosines are as follows. The vertices of the triangle are labeled with single upper-case letters. The side opposite is labeled with the same lower-case letter, or with the two vertices at either end.
Vertex and angle K are opposite side k, also called side NM in this triangle.
Answer:
Fran's upstream speed (against the current):
2.9 km/hr - 0.1 km/hr = 2.8 km/hr
Fran's downstream speed (with the current):
2.9 km/hr + 0.1 km/hr = 3.0 km/hr
Using the distance formula for calculating time:
rate x time = distance
time = distance / rate
Fran's upstream time = 9 / 2.8 = 3.21 hrs
Fran's downstream time = 9 / 3.0 = 3.0 hrs
