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tankabanditka [31]
3 years ago
8

What affect does the "k" value have on the function f(x) = log(x)?

Mathematics
2 answers:
myrzilka [38]3 years ago
4 0
The K value is often found at the end of the formula for instance, f(x) = log(x) +k. The K value moves the graph up or down depending on if it is negative or positive.
sasho [114]3 years ago
3 0

Answer:

The correct option is (B) The "k" value moves the graph up or down.

Step-by-step explanation:

Consider the provided function:

f(x)=log(x)

The graph of the provided function is shown in figure 1.

From figure 1, it can be seen that the domain of the function is all positive real numbers and not defined for the negative values.

The logarithmic function can be shift <em>h</em> units horizontally and <em>k</em> unit vertically for the equation:

f(x)=log_{b}(x+h)+k

Horizontal shift:

For <em>h</em> > 0, graph shift <em>h</em> units left and for <em>h</em> < 0, graph shift <em>h</em> units right.

For better understanding refer to the figure 2.

Vertical shift:

For <em>k</em> > 0, graph shift <em>k</em> units up and for <em>k</em> < 0 graph shift <em>k</em> units down.

For better understanding refer to the figure 3.

Hence, the correct option is (B) The "k" value moves the graph up or down.

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6x+2(x+4)&lt;2x+20 solve for inequality
8_murik_8 [283]

The problem to solve is:

6x+2(x+4)‹2x+20

First, let's work on the left hand side of your inequality, the 6x+2(x+4)

This means, for instance, to see if it can be simplified at all.

Multiply x and 6

Multiply x and 1

The x just gets copied along.

The answer is x

x

6*x evaluates to 6x

x+4 evaluates to x+4

Multiply 2 by x+4

we multiply 2 by each term in x+4 term by term.

This is the distributive property of multiplication.

Multiply 2 and x

Multiply 1 and x

The x just gets copied along.

x

2 × x = 2x

Multiply 2 and 4

1

2 × 4 = 8

2*(x+4) evaluates to 2x+8

6x + 2x = 8x

The answer is 8x+8

6*x+2*(x+4) evaluates to 8x+8

So, all-in-all, the left hand side of your inequality can be written as: 8x+8

Now, let's work on the right hand side of your inequality, the 2x+20

Multiply x and 2

Multiply x and 1

The x just gets copied along.

The answer is x

x

2*x evaluates to 2x

2*x+20 evaluates to 2x+20

The right hand side of your inequality can be written as: 2x+20

So with these (any) simplifications, the inequality we'll set out to solve is:

8x+8 ‹ 2x+20

Move the 8 to the right hand side by subtracting 8 from both sides, like this:

From the left hand side:

8 - 8 = 0

The answer is 8x

From the right hand side:

20 - 8 = 12

The answer is 12+2x

Now, the inequality reads:

8x ‹ 12+2x

Move the 2x to the left hand side by subtracting 2x from both sides, like this:

From the left hand side:

8x - 2x = 6x

The answer is 6x

From the right hand side:

2x - 2x = 0

The answer is 12

Now, the inequality reads:

6x ‹ 12

To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

around the x on the left side of the inequality.

The last step is to divide both sides of the inequality by 6 like this:

To divide x by 1

The x just gets copied along in the numerator.

The answer is x

6x ÷ 6 = x

12 ÷ 6 = 2

The solution to your inequality is:

x ‹ 2

So, your solution is:

x must be less than 2The problem to solve is:

6x+2(x+4)‹2x+20

First, let's work on the left hand side of your inequality, the 6x+2(x+4)

This means, for instance, to see if it can be simplified at all.

Multiply x and 6

Multiply x and 1

The x just gets copied along.

The answer is x

x

6*x evaluates to 6x

x+4 evaluates to x+4

Multiply 2 by x+4

we multiply 2 by each term in x+4 term by term.

This is the distributive property of multiplication.

Multiply 2 and x

Multiply 1 and x

The x just gets copied along.

x

2 × x = 2x

Multiply 2 and 4

1

2 × 4 = 8

2*(x+4) evaluates to 2x+8

6x + 2x = 8x

The answer is 8x+8

6*x+2*(x+4) evaluates to 8x+8

So, all-in-all, the left hand side of your inequality can be written as: 8x+8

Now, let's work on the right hand side of your inequality, the 2x+20

Multiply x and 2

Multiply x and 1

The x just gets copied along.

The answer is x

x

2*x evaluates to 2x

2*x+20 evaluates to 2x+20

The right hand side of your inequality can be written as: 2x+20

So with these (any) simplifications, the inequality we'll set out to solve is:

8x+8 ‹ 2x+20

Move the 8 to the right hand side by subtracting 8 from both sides, like this:

From the left hand side:

8 - 8 = 0

The answer is 8x

From the right hand side:

20 - 8 = 12

The answer is 12+2x

Now, the inequality reads:

8x ‹ 12+2x

Move the 2x to the left hand side by subtracting 2x from both sides, like this:

From the left hand side:

8x - 2x = 6x

The answer is 6x

From the right hand side:

2x - 2x = 0

The answer is 12

Now, the inequality reads:

6x ‹ 12

To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

around the x on the left side of the inequality.

The last step is to divide both sides of the inequality by 6 like this:

To divide x by 1

The x just gets copied along in the numerator.

The answer is x

6x ÷ 6 = x

12 ÷ 6 = 2

The solution to your inequality is:

x ‹ 2

So, your solution is:

x must be less than 2

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3 years ago
ILL GIVE BRAINLIST PLS:/which of the following statements about xy and xx is true ?
vfiekz [6]

Answer:

i think its b or c gl... hope b is right

8 0
3 years ago
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If 6x = -54, what is the value of x?<br> -9<br> -7<br> 7<br> 9
andrezito [222]
I believe this is -9, I did -54 divided by 6.
3 0
3 years ago
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bezimeni [28]
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3 years ago
Fill in the blank.<br> (5x)2<br> a0x2
Yuki888 [10]

Answer:a_0=25

Step-by-step explanation:

It is given that, (5x)^2=a_0x^2

We need to find the value of a_0

As (5x)^2=a_0x^2

Solving LHS

25x^2=a_0x^2

Now comparing the coefficients of x^2

In LHS the coefficient of x^2 is 25

In RHS the coefficient of x^2 is a_0

It implies that, a_0=25

So, the value of a_0 is 25.

5 0
3 years ago
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