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tankabanditka [31]
3 years ago
8

What affect does the "k" value have on the function f(x) = log(x)?

Mathematics
2 answers:
myrzilka [38]3 years ago
4 0
The K value is often found at the end of the formula for instance, f(x) = log(x) +k. The K value moves the graph up or down depending on if it is negative or positive.
sasho [114]3 years ago
3 0

Answer:

The correct option is (B) The "k" value moves the graph up or down.

Step-by-step explanation:

Consider the provided function:

f(x)=log(x)

The graph of the provided function is shown in figure 1.

From figure 1, it can be seen that the domain of the function is all positive real numbers and not defined for the negative values.

The logarithmic function can be shift <em>h</em> units horizontally and <em>k</em> unit vertically for the equation:

f(x)=log_{b}(x+h)+k

Horizontal shift:

For <em>h</em> > 0, graph shift <em>h</em> units left and for <em>h</em> < 0, graph shift <em>h</em> units right.

For better understanding refer to the figure 2.

Vertical shift:

For <em>k</em> > 0, graph shift <em>k</em> units up and for <em>k</em> < 0 graph shift <em>k</em> units down.

For better understanding refer to the figure 3.

Hence, the correct option is (B) The "k" value moves the graph up or down.

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7 0
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What methods do stock analysts use to value an asset if they calculate profit minus the cost of capital?
Elan Coil [88]

Answer:

Economic Value Added (EVA)

4 0
3 years ago
31=4-9y I need help sorry
Drupady [299]

Answer:

y=-3

Step-by-step explanation:

31=4-9y

9y=4-31

9y=-27

y=-27/9

y=-3

8 0
3 years ago
the number of kilometers a car can drive varies directly with the liters of fuel in the car. this car can travel 476 kilometers
notka56 [123]

For this case we have that the relationship is direct.

Therefore, we have:

y = k * x

Where,

y: distance traveled in kilometers

x: number of liters of fuel

k: proportionality constant

We must look for the value of k. For this, we use the following data:

This car can travel 476 kilometers on 17 liters of fuel.

Substituting values we have:

476 = k * 17

From here, we clear the value of k:

k = \frac{476}{17}\\k = 28

Therefore, the relationship is:

y = 28x

For 1428 kilometers we have:

1428 = 28x

Clearing the amount of fuel we have:

x = \frac{1428}{28}\\x = 51

Answer:

51 liters of fuel are required for the vehicle to travel 1,428 kilometers

3 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
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