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WITCHER [35]
3 years ago
10

Which are the solutions of the quadratic equation? x2 = 9x + 6 StartFraction negative 9 minus StartRoot 105 EndRoot Over 2 EndFr

action comma StartFraction negative 9 + StartRoot 105 EndRoot Over 2 EndFraction StartFraction negative 9 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFraction negative 9 + StartRoot 57 EndRoot Over 2 EndFraction StartFraction 9 minus StartRoot 105 EndRoot Over 2 EndFraction comma StartFraction 9 + StartRoot 105 EndRoot Over 2 EndFraction StartFraction 9 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFraction 9 + StartRoot 57 EndRoot Over 2 EndFraction
Mathematics
2 answers:
Artyom0805 [142]3 years ago
7 0

Answer:

<u>The correct answer is C. 9 -√ 105/ 2,  9 + √ 105/ 2</u>

Step-by-step explanation:

Let's find the solutions for the quadratic equation:

x² = 9x + 6

x² - 9x -6 = 0

Using the quadratic formula, we have:

x = [- (-9) +/- √ (-9)² - 4 * 1 * -6]/2 * 1

x = [ 9 +/- √ (81 + 24]/2

x = [ 9 +/- √ (105]/2

<u>x₁  =  [ 9 + √ (105]/2</u>

<u>x₂ =  [ 9 - √ (105]/2</u>

<u>The correct answer is C. 9 -√ 105/ 2,  9 + √ 105/ 2</u>

Note: Same answer to question 14133688, answered by me today.

crimeas [40]3 years ago
6 0

Answer:

c

Step-by-step explanation:

You might be interested in
What is the discriminant of the polynomial below? 2x^2+3x-7
Katena32 [7]

Answer:

Option C. 65

Step-by-step explanation:

we know that

The discriminant of a quadratic equation of the form ax^{2} +bx+c=0 is equal to

D=b^{2}-4ac

in this problem we have

2x^{2} +3x-7  

so

a=2\\b=3\\c=-7

substitute

D=3^{2}-4(2)*(-7)

D=9+56

D=65

7 0
3 years ago
How to solve this ? (2√2 *√(3+x) )^2
lianna [129]
( 2\sqrt{2}) ^{2} *  (\sqrt{3 + x} )^{2} = 8 * (3+x) = 24 + 8x
5 0
3 years ago
Read 2 more answers
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scoundrel [369]
She bought 4 coffees! :)
7 0
2 years ago
WILL MARK BRAINLIEST
Nutka1998 [239]

Answer:

a² + b² = 68

a3 + b3 = 520

Step-by-step explanation:

Given :

a + b = 10 (1)

ab = 16 (2)

A. Find a² + b²

(a + b)² = a² + 2ab + b² (3)

Substitutite the values of (1) and (2) into (3)

(10)² = a² + 2(16) + b²

100 = a² + 32 + b²

Subtract 32 from both sides

100 - 32 = a² + b²

a² + b² = 68

B. a^3 + b^3

(a + b)^3 = a^3 + b^3 + 3ab(a + b)

(10)^3 = a^3 + b^3 + 3*16(10)

1000 = a^3 + b^3 + 480

a^3 + b^3 = 1000 - 480

a3 + b3 = 520

5 0
2 years ago
Can someone please answer. There is a picture. There is only one problem. Thank you so much!!!
kvasek [131]
Hello,

Answer D

x²/25+y²/16=1

5 0
3 years ago
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