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RideAnS [48]
4 years ago
10

Gauss elimination process

Computers and Technology
1 answer:
kakasveta [241]4 years ago
6 0
In linear algebra, Gaussian elimination<span> (also known as row reduction) is an algorithm for solving systems of linear equations. It is usually understood as a sequence of operations performed on the corresponding matrix of coefficients.</span>
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A. the ability to quickly restore service following a service failure and provide compensation.

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Systems like servers are bound to fail at some point. This is because, it either has running parts or electronic components that could overheat or get shorted due to external or internal malfunction.

The ability of system to quickly restore services and operation after it experiences a total system failure is called system recovery.

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Why does the phrase "compatibility mode” appear when opening a workbook?
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Read 2 more answers
Write a complete program that asks the user to input the height and radius of a cone (both of type double) and calls two individ
Vika [28.1K]

Answer:

The program in C++ is as follows:

#include <iostream>

#include <math.h>

using namespace std;

double area(double r, double h){

   double A = 3.14 * r * (r + sqrt(h*h + r*r));

   return A;}

double volume(double r, double h){

   double V = (1.0/3) * 3.14 * r*r * h;

   return V;}

int main(){

   double radius, height;

   cout<<"Radius: "; cin>>radius;

   cout<<"Height: "; cin>>height;

   cout<<"Area: "<<area(radius,height)<<endl;

   cout<<"Volume: "<<volume(radius,height);

   return 0;

}

Explanation:

This declares the area function

double area(double r, double h){

Calculate area

   double A = 3.14 * r * (r + sqrt(h*h + r*r));

Return the calculated area

   return A;}

This declares the volume method

double volume(double r, double h){

Calculate volume

   double V = (1.0/3) * 3.14 * r*r * h;

Return the calculated volume

   return V;}

The main begins here

int main(){

Declare radius and height

   double radius, height;

Get input for radius

   cout<<"Radius: "; cin>>radius;

Get input for height

   cout<<"Height: "; cin>>height;

Call the area function and print the returned value for area

   cout<<"Area: "<<area(radius,height)<<endl;

Call the volume function and print the returned value for volume

   cout<<"Volume: "<<volume(radius,height);

   return 0;

}

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3 years ago
Editing is important because it allows you to
asambeis [7]
Answer A is the answer, as it combines all choices in the list. One can check the overall structure.
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