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3 years ago

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What is the spreading rate between North America and Europe

1 answer:

Ganezh [65]3 years ago

8 0

The speed at which new ocean floor is created varies from one location on the ocean ridge to another. Between North America and Europe, the rate is about 2.2 inches (3.6 cm) per year. At the East Pacific rise, which is pushing a plate into the west coast of South America, the rate is 12.6 inches (32.2 cm) per year.

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3 years ago

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2 years ago

An energy inefficient incandescent light bulb uses a hot filament to produce a continuous spectrum. The temperature of the filam

ad-work [718]

Answer:

So the wavelength of light is 1015.7 nm

Explanation:

From Wein's displacement law, we can write the following formula;

$\lambda _{MAX}\times T=K$ here, $\lambda _{MAX}$ is the wavelength of maximum radiation in meters

T is the absolute temperature (in Kelvin) for maximum radiation

K is the constant has a value of $2.898\times 10^{-3}m-kelvin$

Given here, T = 2853 K

And we need to find $\lambda _{MAX}$

Putting the values in formula

$\lambda _{max}\times 2853=2.898\times 10^{-3}$

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3 years ago

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tamaranim1 [39]

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3 years ago

2 1. Scattering cross-section of acrosol particles is 2.5E-12 m , absorption cross-section is 0.45E- .2 12 m Concentration of pa

Alona [7]

Answer:

$T = 3.23 \times 10^{-83}$

Explanation:

thickness of aerosol layer is 2.5 km

zenith angle is 40 degree

we know that

$\tau = \epsilon_{ext} . h$

where

$\epsilon_{ext} = N.\sigma_{ext}$

$\epsilon_{ext}$ is extinction coefficient

$\sigma_{ext}$ extiction cross section

N = Concentration

$\sigma_{ext} = (2.5 + 0.45)\times 10^{-12} m^2$

$= 2.95 \times 10^{-12} m^2$

$\epsilon_{ext} = 2\times 10^7 \times 2.95 \times 10^{-12} m^2 \times m^{-3}$

$= 5.9 \times 10^{-5} m^{1}$

$\tau = 5.9 \times 10^{-5} m^{-1} \times 2.5\times 10^3 m$

$= 14.75\times 10^{-2}$

transimiitance $T = e^{\frac{-\tau}{\mu}}$

$T = e^{\frac{- 14.75 \times 10^{-2}}{cos 40}}$

$T = 3.23 \times 10^{-83}$

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3 years ago