Former NFL punter Ray Guy holds the record for the longest hangtime on a punt. If the ball leaves with an upward velocity of 128
ft/s from an initial height of 4 feet, how long will the ball be in the air? Use the formula H= -16t(squared) +128t +4, where h is the height of the ball in feet and t is the time in seconds since it is kicked. Round your answer to the nearest tenth.
<span>Since we have the formula for height, all we need to do is solve for t when the height of the ball is 0, meaning it is on the ground.
The equation is H = -16t^2 + 128t + 4
Substituting H for 0, we get: 0 = -16t^2 + 128t + 4
Now the problem becomes a simple quadratic equation that we can solve using the quadratic formula.
The quadratic formula for at^2 + bt + c = 0 is:
t = [-b +/- sqrt(b^2 - 4ac)] / 2a
Plugging in a, b, and c, we get
t = [-128 +/- sqrt(128^2 - 4*-16*4)] / -32
Solving for t, we get t = 8.03, -0.03. Since the time must be positive, the answer is 8.0. The ball is in the air for 8.0 seconds</span>
probably there would be more carbon in the air and trees help collect carbon. Also if you cut down trees some people cut it by burning it down and if that happens you are making more carbon which is affecting the atmosphere