All categories

3 years ago

Si 2/3 de los 84 pasajeros de un bus de Transmilenio son hombres, ¿cuántas

Mathematics

1 answer:

Rina8888 [55]3 years ago

7 0

Answer:

Step-by-step explanation:

Aquí, tenemos 2/3 como hombres.

La fracción de mujeres es, por lo tanto, 1-2 /3 = 1/3

Entonces 1/3 de 84 son mujeres Por lo tanto, el número de mujeres es 1/3 * 84 = 28

You might be interested in

What is m∠N?<br> A. 19°<br> B. 68°<br> C. 95°<br> D. 112°

Gennadij [26K]

It would be B. 68

I hope this help!

6 0

3 years ago

Find the surface area! Please I need it quick

zloy xaker [14]

Step-by-step explanation:

<h2>We first find the area of a trapezium and rectangular face</h2><h2>Fourmula to find the are of a trapezium is:</h2><h3>Area=1/2*(B+b)*h</h3><h3> =1/2*3.7*1.9</h3><h3> =3.515m²</h3><h2 /><h2>Since every rectangular face is different we gotta find each of them</h2>

<h3 /><h3>Now we find the area of the whole prism</h3><h3>Area=3.515*2+10.08+6.72+11.05+9.12</h3><h3>Area=44m²</h3>

<h2>Sorry my wireless went down!!!</h2><h2>Hope this helps and you already know what I would like to get</h2>

7 0

3 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

3 0

3 years ago

Who can help me out on this please??

Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

4+6 does not equal 12 so there for it is incorrect

8 0

3 years ago

The hall has 10 windows that measure 2m across and 2m high. It also has 4

mina [271]

Multiply all of that and that’s your answer

6 0

3 years ago