4/133. As you remove each ball from the bucket, the total number of balls goes down by 1.
the equation should be
(number of balls of targeted color / all balls in the bucket)
And as you take 4 times, you have to do this for 4 times
X^2+8x=10
X^2+8x-10=0
(X^2+8x+16-16)-10=0
(X^2+8x+16)-16-10
(X+4)^2-26
Hope this helps!
Answer:
a) one solution
b) no solution
Step-by-step explanation:
Systems of equations can be described as having one solution, no solution or infinite solutions:
One solution: 'x' and 'y' are equal to only one value
No solution: 'x' and 'y' can not be solved with the given equations
Infinite solutions: values for 'x' and 'y' include all real numbers
In order to evaluate the systems, putting them in the same format is your first step:
a) - y = -5x - 6 or y - 5x = 6
y - 5x = -6
Since both equations have the same expression 'y - 5x', but there are equal to opposite values, this system would have no solution, as this would not be possible to calculate.
b) y + 3x = -1
y = 3x -1 or y - 3x = -1
Solving for 'y' by adding the equations and eliminating 'x', gives us:
2y = -2 or y = -1
Using y = -1 to plug back into an equation and solve for 'x': -1 + 3x = -1 or x = 0. Since 'x' and 'y' can be solved for a value, the system has just one solution.
True
_____
You need to test for some combination of the variables present. If one is missing, you can only test a value of the other.
Answer:
Step-by-step explanation:
= 7-w
( )^2 = (7-w)^2
g = (7-w)^2
