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alexandr1967 [171]
3 years ago
11

If one of the variables in a linear inequality in two variables is not presented because its coefficient is understood to be 0,

it is only necessary to test a value of the other coordinate to determine which side of the line is the shaded region. true or false
Mathematics
1 answer:
Korolek [52]3 years ago
4 0
True

_____
You need to test for some combination of the variables present. If one is missing, you can only test a value of the other.
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A demand loan for $8,944.61 with interest at 7.8% compounded semi-annually is repaid after two years, seven months. What is the
disa [49]

Answer:

the correct answer is option D which is $1,954.94

Step-by-step explanation:

loan amount =  $8,944.61

interest =  7.8% = 7.8 %/2 = 3.9 %

compounded semi annually =  2 × 12 + 7 = 31 months

                         time = 31/6 months

I =P(1+\dfrac{r}{100})^{\frac{31}{6}}-P\\ \\I =  8994.61(1+\dfrac{3.9}{100})^{\frac{31}{6}}-8994.61 \\I =1954.94

hence, the correct answer is option D which is $1,954.94

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4 years ago
The graph below shows the distance that Emilio is from his home as a function of time throughout one day. If Emilio begins his d
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Answer: 20

Step-by-step explanation:

I did it in prep works

5 0
3 years ago
Londynnorth londynnorth Middle School Mathematics 5+3 pts NEED HELP ASAP BRAINLEIST Solve and graph the absolute value inequalit
Andrej [43]
Number line with closed dots on negative 1.5 and 1 with shading in between.
3 0
3 years ago
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In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence
Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

\hat p =\frac{12}{300}=0.04

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The critical value of <em>z</em> for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0
3 years ago
Kai spent 90% of his money on a laptop that cost $423. Does he have enough money left to buy a scanner.explain
GarryVolchara [31]
Okay, so:

You would want to find what 1/10 of the laptop costs. That would be the 10% of money left in Kai's account.

So,

423*.1

(you have to turn the percentage into a decimal; 10%= .10


423*.1= 42.3

So, Kai has 42.3 dollars left to buy a scanner. He only has 10% of his bank account left to spend on the scanner.

I hope this helps!
~cupcake
7 0
4 years ago
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